我目前失去如何做到這一點,需要幫助,但我目前正在建立一個離子應用程序,並通過PHP腳本獲取信息時存儲在數據庫上的信息我收到我想轉換的JSON一個不錯的格式化的HTML表通過PHP將JSON輸出轉換爲HTML表格?
這是我的PHP
<?php
header("Access-Control-Allow-Headers: Content-Type");
header("Access-Control-Allow-Methods: GET, POST, OPTIONS");
header("Access-Control-Allow-Origin: *");
$host = "****";
$user = "*****";
$password = "";
$database = "holes";
$connect = mysqli_connect($host,$user,$password,$database) or die("Problem connecting.");
$result = mysqli_query($connect, "SELECT * from hole18") or die("Bad Query.");
mysqli_close($connect);
$results = array();
while($row = mysqli_fetch_assoc($result))
{
$results[] = $row;
}
echo json_encode($results);
?>
而這裏的JSON輸出:
[{"index":"1","Par":"4","FIR":"1","GIR":"1","Score":"3","puttsno":"1","bunkershit":"0","oob":"0"}]
請幫我
試試這個:'$ JSON =的file_get_contents( 'url_here'); $ obj = json_decode($ json); echo $ obj-> index;'其中'url_here'將成爲你寫的php文件的路徑。 – Nerazzurri