當我做這個,我不斷收到此錯誤:解析錯誤:語法錯誤,意外'(T_ENCAPSED_AND_WHITESPACE),預計標識符(T_STRING)或可變
<?php
$info = $_POST['mname'];
$info = ucwords($info);
// Make a MySQL Connection
mysql_connect("localhost", "user", "password") or die(mysql_error());
mysql_select_db("javadatest") or die(mysql_error());
// Get a specific result from the "example" table
$result = mysql_query("SELECT * FROM movieList
WHERE name = '$info'") or die(mysql_error());
// get the first (and hopefully only) entry from the result
$row = mysql_fetch_array($result);
// Print out the contents of each row into a table
//echo $row['name']." ".$row['year']." ".$row['genre'];
echo "
<script language=javascript>
var jsvar;
jsvar = <?php echo $row['name'], $row['year'], $row['genre'];?>
function buy() {
window.location = \"https://www.paypal.com\";
alert(\"Thanks for shopping at Movie Store\");
}
var myWindow = window.open('', '', 'width = 300, height = 300);
myWindow.document.write(jsvar);
myWindow.document.write('<body>');
myWindow.document.write('<input type="button" value="Buy" onclick=/"buy()/">');
myWindow.document.write('</body>');
//myWindow.buy = buy;
</script>
";
?>
我想在PHP中使用JavaScript通過將我的JavaScript代碼放入我的echo語句中。我無法弄清楚我做錯了什麼。任何幫助,將不勝感激。
'$ _POST ['mname'] =「或1 = 1」'。繁榮! – elclanrs 2013-04-10 03:47:50
我喜歡類似問題的代表點 – zerkms 2013-04-10 03:49:14
@elclanrs現在他們可以看到所有的電影xD – Musa 2013-04-10 03:54:04