比較行結果並創建新列

Question

我想比較行結果並在特定列具有相同的fightID時創建新列。

我的查詢：

 
Fight Fight Date Player PlayerScore 
1  2014-10-10 Kevin 8 
1  2014-10-10 Chris 4 
2  2014-09-01 Kevin 8 
2  2014-09-01 Eric 4 

我想要的結果：

 
Fight Fight Date Player1 Result1 Player2 Result2 
1  2014-10-10 Kevin 8  Chris 4 
2  2014-09-01 Kevin 8  Eric 4 

順便說一句 - 我是新來的，一般

PHP/MySQL和編程PHP

SELECT fight.fightdato, fight.fightID, players.name, 
     playersfight.playerid, playersfight.playerScore 
FROM fight 
INNER JOIN playersfight ON fight.fightID = playersfight.fightID 
INNER JOIN players ON playersfight.playerID = players.playersID 

結果

Thanks fo fo幫助我！

Answer 1

您需要再次加入player和playerfight表格。

是這樣的：在一排

1. 結果與加入同一玩家兩次：

   SELECT fight.fightID, fight.fightdato, 
        p1.name as 'Player_1', pf1.playerid as 'PlayerID_1', pf1.playerScore as 'Result_1', 
        p2.name as 'Player_2', pf2.playerid as 'PlayerID_2', pf2.playerScore as 'Result_2'   
   FROM fight 
   JOIN playersfight pf1 ON fight.fightID = pf1.fightID 
   JOIN players p1  ON pf1.playerID = p1.playersID 
   JOIN playersfight pf2 ON fight.fightID = pf2.fightID 
   JOIN players p2  ON pf2.playerID = p2.playersID 
   WHERE p1.playersID < p2.players2 
   

   的WHERE條款與條件p1.playersID < p2.players2排除兩種情況，我們不想回來了。

2. 重複 - 例如對於身份證號碼爲1和2的玩家，將返回與玩家ID爲(1,2)和(2,1)兩次相同的戰鬥。現在它只會返回第一個排列。