顯示來自mysql查詢的部分結果

Question

我有一個sql查詢，它從3個不同的表中抽取所有類型的數據，我現在想在數組中顯示這些數據。我可以從sql查詢中輸出所有數據，但我只想根據表中列的值是否相同來一次顯示數組的一部分。下面將嘗試演示。

我的SQL結果看起來是這樣的：

Client | Order | Exc1 | Exc2 | Rest | Reps | 
------------------------------------------------------- 
Steve | 1A  | this | That | This | that | 
------------------------------------------------------- 
Mike | 1A  | this | That | This | that | 
------------------------------------------------------- 
Jax  | 1A  | this | That | This | that | 
------------------------------------------------------- 
Steve | 1B  | this | That | This | that | 
------------------------------------------------------- 
Mike | 1B  | this | That | This | that | 
------------------------------------------------------- 
Jax  | 1B  | this | That | This | that | 

我希望我的陣列來輸出這在第1頁

Steve | 1A  | this | That | This | that | 
------------------------------------------------------- 
Mike | 1A  | this | That | This | that | 
------------------------------------------------------- 
Jax  | 1A  | this | That | This | that | 

這2頁等上。每個頁面將包含所有客戶的列表，每個頁面只有一個訂單值。每個用戶的訂單欄值會有所不同，因爲他們可以爲訂單字段輸入自己的文本。這是可能的，如果是這樣，最好的方式是怎樣的？

@Gordon Linoff這裏是我目前的查詢。我真的不明白你寫了什麼或更多的與我的查詢有關。在我目前的查詢ID下面。我沒有完成輸出到數組中。我在測試之前就擁有了這個功能，直到我獲得了我想要的結果。

function get_workout_class(){ 
$workout_class = array(); 

$workout_query = mysql_query(" 
SELECT * 
FROM `movements` 
LEFT JOIN `classes` 
ON `movements`.`class_id` = `classes`.`class_id` 
LEFT JOIN `clients` 
ON `movements`.`class_id` = `clients`.`class_id` 
WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." 
ORDER BY `movements`.`order`, `clients`.`first_name` 

"); 

}

這裏是我的查詢結果的屏幕截圖，所以你可以看到我是多麼希望他們分組。頁面按不同的「順序」值拆分。客戶數量因班級而異。

http://custommovement.com/help/query.png

這是我的新的查詢。第一部分工作正常，但子查詢給我的問題。它不拉任何結果。 @GordonLinoff

function get_workout_class($class_id){ 
$class_id = (int)$class_id; 

$workout_class = array(); 

$workout_query = mysql_query(" 
WITH `workouts` as (
SELECT 
`movements`.`movement_id`, 
`movements`.`order`, 
`movements`.`mv_00`, 
`movements`.`mv_01`, 
`movements`.`mv_02`, 
`movements`.`mv_03`, 
`movements`.`mv_04`, 
`movements`.`rep_set_sec`, 
`movements`.`rest`, 
`classes`.`class_name`, 
`clients`.`client_id`, 
`clients`.`first_name`, 
`clients`.`last_name`, 
`clients`.`nickname` 
FROM `movements` 
LEFT JOIN `classes` ON `movements`.`class_id` = `classes`.`class_id` 
LEFT JOIN `clients` ON `movements`.`class_id` = `clients`.`class_id` 
WHERE `classes`.`class_id` = '$class_id' 
) 

SELECT `wo`.* 
(SELECT COUNT(DISTINCT `order`) FROM `workouts` `wo2` WHERE `wo2`.`order` <= `wo`.`order`) as `pagenum` 
FROM `workouts` `wo` 
ORDER BY `pagenum` 

"); 

echo mysql_num_rows($workout_query); 
} 

Answer 1

我想你可以通過添加頁碼查詢解決您的問題。不幸的是，這在mysql中是非常痛苦的，因爲你必須使用自加入或相關的子查詢。

下面是如何與相關子查詢做到這一點的例子：

select t.*, 
     (select count(distinct order) from t t2 where t2.order <= t.order) as pagenum 
from t 
order by pagenum 

根據您的原始查詢（但不把它變成一個字符串）：

with workouts as (
    SELECT * 
    FROM `movements` LEFT JOIN 
      `classes` 
      ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN 
      `clients` 
      ON `movements`.`class_id` = `clients`.`class_id` 
     WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." 
    ) 
select wo.*, 
     (select count(distinct order) from workouts wo2 where wo2.order <= wo.order) as pagenum 
from workouts wo 
order by pagenum 

這幾乎工作。 。 。只是一個警告。您可以將「SELECT *」放入with子句中，因爲您有多個具有相同名稱的列。放入你需要的列。

我忘記了mysql不支持「with」語句。我對不好的語法表示歉意。解決辦法之一是使用視圖或臨時表。否則，查詢有點複雜，因爲邏輯必須重複兩次：

select wo.*, 
     (select count(distinct order) 
     from (SELECT * 
       FROM `movements` LEFT JOIN 
        `classes` 
        ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN 
        `clients` 
        ON `movements`.`class_id` = `clients`.`class_id` 
       WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." 
      ) wo2 
     where wo2.order <= wo.order 
     ) as pagenum 
from (SELECT * 
     FROM `movements` LEFT JOIN 
      `classes` 
      ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN 
      `clients` 
      ON `movements`.`class_id` = `clients`.`class_id` 
     WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']." 
    ) wo 
order by pagenum 

Answer 2

試試這個。它使用子查詢作爲訂單的最大值。

SELECT a.* 
FROM myTable a INNER JOIN 
      (
       SELECT Client, 
         Max(`Order`) as MaxOrder 
       FROM myTable 
       GROUP BY Client 
      ) c 
       ON a.Client = c.Client AND 
        a.`Order` = c.MaxOrder 

或simpliest如果我沒有記錯

SELECT * 
FROM myTable 
WHERE `Order` = '1B'