如何使這個SQL函數更快地解析XML

Question

我很難找到一種方法將此自定義SQL腳本改進爲Umbraco數據庫。

下面是sql腳本獲取並解析XML，並選擇正確的值：

DECLARE @Title nvarchar(1000) 
SET @Title = 
(SELECT @NodeXml.query('//TechnicalData/title').value('.', 'nvarchar(max)') Title 
FROM cmsContentXml xt JOIN umbracoNode un ON un.id = xt.NodeId 
WHERE xt.nodeId = @NodeId) 

SELECT iif(CHARINDEX('"values":null', @Title,0) > 0,'',Substring(@Title, 21, CHARINDEX('}', @Title) - 22)) Title 

的部分XML如下：

<?xml version="1.0"?> 
<TechnicalData id="1261" key="b6a2f67a-0f0f-40dd-a3c6-c5fb9d8b78b9" parentID="1092" level="3" creatorID="0" sortOrder="12" createDate="2016-07-14T13:56:37" updateDate="2016-07-15T12:06:25" nodeName="Rioolkolken Type 1 Drainerend via de zijwanden" urlName="rioolkolken-type-1-drainerend-via-de-zijwanden" path="-1,1089,1092,1261" isDoc="" nodeType="1154" creatorName="admin" writerName="Karl" writerID="1" template="1085" nodeTypeAlias="TechnicalData"> 
    <title>{"values":{"nl-BE":"Rioolkolken Type 1 Drainerend via de zijwanden"},"dtdGuid":"f2dfa88e-63b9-4913-80cd-64d770cef90e"}</title> 
</TechnicalData> 

這只是一個小部分腳本。 TechnicalData包含大約20個節點，所有節點都必須解析。可以找到完整的腳本here

此自定義腳本的原因是因爲我需要使用ssrs報告來擴展Umbraco站點。

Answer 1

你的方法是緩慢的，因爲你一遍又一遍採取的信息的一個單比特出你的XML。

使用此功能，您將獲得所有數據類型安全從一個sinlge去掉你的XML並且沒有任何字符串解析。

DECLARE @NodeXml XML= 
N'<?xml version="1.0"?> 
<TechnicalData id="1261" key="b6a2f67a-0f0f-40dd-a3c6-c5fb9d8b78b9" parentID="1092" level="3" creatorID="0" sortOrder="12" createDate="2016-07-14T13:56:37" updateDate="2016-07-15T12:06:25" 
nodeName="Rioolkolken Type 1 Drainerend via de zijwanden" urlName="rioolkolken-type-1-drainerend-via-de-zijwanden" path="-1,1089,1092,1261" isDoc="" nodeType="1154" creatorName="admin" writerName="Karl" writerID="1" template="1085" nodeTypeAlias="TechnicalData"> 
    <title>{"values":{"nl-BE":"Rioolkolken Type 1 Drainerend via de zijwanden"},"dtdGuid":"f2dfa88e-63b9-4913-80cd-64d770cef90e"}</title> 
</TechnicalData>'; 

SELECT td.value('@id','int') AS id 
     ,td.value('@key','uniqueidentifier') AS [key] 
     ,td.value('@parentID','int') AS parentID 
     ,td.value('@level','int') AS [level] 
     ,td.value('@creatorID','int') AS creatorID 
     ,td.value('@sortOrder','int') AS sortOrder 
     ,td.value('@createDate','datetime') AS createDate 
     ,td.value('@updateDate','datetime') AS updateDate 
     ,td.value('@nodeName','nvarchar(max)') AS nodeName 
     ,td.value('@urlName','nvarchar(max)') AS urlName 
     ,td.value('@path','nvarchar(max)') AS [path] 
     ,td.value('@isDoc','nvarchar(max)') AS isDoc 
     ,td.value('@nodeType','int') AS nodeType 
     ,td.value('@creatorName','nvarchar(max)') AS creatorName 
     ,td.value('@writerName','nvarchar(max)') AS writerName 
     ,td.value('@writerID','int') AS writerID 
     ,td.value('@template','int') AS template 
     ,td.value('@nodeTypeAlias','nvarchar(max)') AS nodeTypeAlias 

     ,td.value('title[1]','nvarchar(max)') AS Title 

FROM @NodeXml.nodes('TechnicalData') AS A(td) 

在這種情況下的結果是一行，所有數據在列中。

我懷疑，你需要自己的價值觀聲明的變量，更好地運用上述的CTE（一套基於/在線/特設在大多數情況下比程序），並從那裏使用的值。但是：很容易將收集的信息填充到已聲明的變量中（如果確實需要的話）。在這種情況下，只需聲明正確類型的變量並使用語法

SELECT @MyVariable=td.value('@id','int') 
     ,@OtherVariable= ... 
... same for the rest... 

Answer 2

解析在一個單一的所有節點選擇

DECLARE @NodeXml xml; 

-- sample data 
SET @NodeXml ='<TechnicalData id="1261" key="b6a2f67a-0f0f-40dd-a3c6-c5fb9d8b78b9" parentID="1092" level="3" creatorID="0" sortOrder="12" createDate="2016-07-14T13:56:37" updateDate="2016-07-15T12:06:25" nodeName="Rioolkolken Type 1 Drainerend via de zijwanden" urlName="rioolkolken-type-1-drainerend-via-de-zijwanden" path="-1,1089,1092,1261" isDoc="" nodeType="1154" creatorName="admin" writerName="Karl" writerID="1" template="1085" nodeTypeAlias="TechnicalData"> 
    <title>{"values":{"nl-BE":"Rioolkolken Type 1 Drainerend via de zijwanden"},"dtdGuid":"f2dfa88e-63b9-4913-80cd-64d770cef90e"}</title> 
</TechnicalData>'; 

DECLARE @Title nvarchar(1000); 
DECLARE @Subtitle nvarchar(1000) 
DECLARE @Company int; 
DECLARE @Date Datetime; 

SELECT @Date = @NodeXml.value('(/TechnicalData/@createDate)[1]', 'datetime') 
,@Title = td.node.value('title[1]','nvarchar(max)') 
,@Subtitle = td.node.value('subtitle[1]','nvarchar(max)') 
,@Company = td.node.value('bedrijf[1]','int') 
-- and so on 
FROM @NodeXml.nodes('TechnicalData') td(node); 

--check it 
SELECT @Date,@Title,@Subtitle,@Company ;