錯誤＃29預計C中的表達

Question

代碼片段：

#define ATT_UUID_SIZE     16 

#define ATT_BT_UUID_SIZE     2 

typedef unsigned char uint8; 

typedef struct 
{ 
    uint8 len;     //!< Length of UUID (2 or 16) 
    uint8 uuid[ATT_UUID_SIZE]; //!< 16 or 128 bit UUID 
} attAttrType_t; 

typedef struct 
{ 
    uint16 startHandle; 
    uint16 endHandle; 
    attAttrType_t type; 
} attReadByTypeReq_t; 

attReadByTypeReq_t req; 
req.startHandle=svcStartHdl; 
req.endHandle=svcEndHdl; 
req.type.len=ATT_BT_UUID_SIZE; 
req.type.uuid[ATT_BT_UUID_SIZE]={0xAD,0x2B}; 

=>它說錯誤＃29時，我給你寫0xAD和0x2B訪問爲的uuid我能怎麼做？錯

Answer 1

req.type.uuid[ATT_BT_UUID_SIZE]={0xAD,0x2B}; 

此行不正確。 uuid [xxx]的uuid是一個數組地址，不能通過'='方法賦值。這樣做：

req.type.uuid[0] = 0xAD; 
req.type.uuid[1] = 0x2B; 

或像這樣：

memcpy(req.type.uuid, YOUR_VALUE, ATT_BT_UUID_SIZE);