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傢伙我使用的jqGrid ......我只希望沒有首先選擇整排在點擊圖像上獲得該行的ID ..這裏是我的代碼獲得該行的ID上點擊
<script type="text/javascript">
$(document).ready(function() {
$("#jqGrid").jqGrid({
url: 'data.json',
datatype: "json",
styleUI: "Bootstrap",
colModel: [{
label: 'Order ID',
name: 'OrderID',
key: true,
width: 75,
hidden: true
}, {
label: 'From Date',
name: 'FromDate',
width: 150,
editable: true,
edittype: "text",
id: "ui-datepicker-div",
editoptions: {
dataInit: function(element) {
$(element).datepicker({
autoclose: true,
format: 'yyyy-mm-dd',
orientation: 'auto bottom'
});
},
},
}, {
label: 'To Date',
name: 'ToDate',
width: 150,
editable: true,
edittype: "text",
editoptions: {
dataInit: function(element) {
$(element).datepicker({
autoclose: true,
format: 'yyyy-mm-dd',
orientation: 'auto bottom'
});
},
},
}, {
label: 'Customer ID',
name: 'CustomerID',
width: 150
}, {
label: 'Ship Name',
name: 'ShipName',
width: 200
}, {
label: 'Row Data',
name: 'RowData',
align: 'center',
formatter: function() {
return "<img src='resources/icon.jpg' onclick='OpenDialog()' alt='Data Row' />";
width = 15;
}
}, ],
loadonce: true,
......
});
});
...........
function OpenDialog() {
var result = "";
var grid = $("#jqGrid");
var rowKey = grid.getGridParam("selrow");
rowData = grid.getLocalRow(rowKey);
for (var item in rowData) {
if (item == 'RowData') {
break;
}
result += rowData[item] + ', ';
}
alert(result);
}任何幫助，請在如何只感謝點擊圖像??上..很多讓行的ID ..謝謝提前