0
final String query = "SELECT " +
"questiontable.QuestionID, questiontable.answer0, questiontable.answer1, questiontable.answer2, questiontable.answer3, questiontable.answer4, questiontable.Correct, " +
" FROM questiontable" +
" WHERE questiontable.QuestionID IN (" +
allQuestionIds +
") ORDER BY questiontable.QuestionID ";
this.cursor = this.db.rawQuery(query, null);
if (this.cursor.moveToFirst()) {
do {
for (final Question q : questions) {
if (q.getQuestionId() == this.cursor.getInt(0)) {
q.addAnswer(new Answer(this.cursor.getString(1),
this.cursor.getString(2),
this.cursor.getString(3),
this.cursor.getString(4),
this.cursor.getString(5),
(this.cursor.getInt(6) == 1 ? true : false)));
}
}
} while (this.cursor.moveToNext());
}
this.cursor.close();
我想補充this.sample(),如:如何使用this.sample() - 而不是this.cursor.getInt()
q.addAnswer(new Answer(this.sample(),
this.cursor.getString(1),
this.cursor.getString(2),
this.cursor.getString(3),
this.cursor.getString(4),
this.cursor.getString(5),
(this.cursor.getInt(6) == 1 ? true : false)));
我想要做的:
*創建,將帶我的整數值(AnswerID)的樣品()方法
* AnswerID將是一個整數值,取整數值QuestionID(this.cursor.getInt(0))及其附近;一個數字從0到4.因此,對於每個QuestionID,我將有5個值(10,11,12,13,14 - 20,21,22,23,24 - ......)
*使用this.sample()
我的代碼是我想象的(也可能是完全錯誤的)
void sample (int AnswerID) {
for (int i = 0; i < 5; i++) {
AnswerID = this.cursor.getInt(0) + i ;
}
this.sample = sample;
}
真的謝謝你的回答。我是新來的Java和其他代碼混淆。 ** numbers.add(cur.getInt(0)); **添加QuestionID Ithink。所以需要使用:numbers.add(cur.getInt(0)+0); numbers.add(cur.getInt(0)+1); numbers.add(cur.getInt(0)2); ....然後** this.sample()=數字; **之後,我將能夠在q.addAnswer方法中使用this.sample()。我對嗎 ? – santral 2013-03-18 14:31:30
我也想問如何將我的數組列表應用到void 將cur.getInt(0)用於我的無效方法嗎? – santral 2013-03-18 15:18:35
@santral爲我的方法調用它this.sample(this.cursor)。 – Oyeme 2013-03-18 15:34:34