反轉方法？

Question

所以我有這個方法....

public static Vector2 cellsToIso(float row, float col) { 
    float halfTileWidth = tileWidth *0.5f; 
    float halfTileHeight = tileHeight *0.5f; 

    float x = (col * halfTileWidth) + (row * halfTileWidth); 
    float y = (row * halfTileHeight) - (col * halfTileHeight); 

    return new Vector2(x,y); 
} 

，我要到反向方法isoToCells(float x, float y)

我想這一點，但它沒有任何意義，我

public static Vector2 isoToCell(float x, float y) { 
    float halfTileWidth = tileWidth * 0.5f; 
    float halfTileHeight = tileHeight * 0.5f; 

    float row = (y/halfTileWidth) - (x/halfTileWidth); 
    float col = (x/halfTileHeight) + (y/halfTileHeight); 

    return new Vector2(row,col); 
} 

Answer 1

float x = (col * halfTileWidth) + (row * halfTileWidth); 
float y = (row * halfTileHeight) - (col * halfTileHeight); 

有了這兩個方程我們可以寫出

x/halfTileWidth = row + col; 
y/halfTileHeight = row - col; 

所以row和column在x和y方面，

row = (1.0/2) * (x/halfTileWidth + y/halfTileHeight); 
column = (1.0/2) * (x/halfTileWidth - y/halfTileHeight); 

在逆方法取代它來獲取row和column回。

public static Vector2 isoToCell(float x, float y) { 
    float halfTileWidth = tileWidth * 0.5f; 
    float halfTileHeight = tileHeight * 0.5f; 

    float row = (1.0/2) * (x/halfTileWidth + y/halfTileHeight); 
    float col = (1.0/2) * (x/halfTileWidth - y/halfTileHeight); 

    return new Vector2(row,col); 
}