自動將所有mysql錶轉儲爲單獨的文件？

Question

我想將每個mysql錶轉儲到單獨的文件中。該手冊指出，其語法是

mysqldump [options] db_name [tbl_name ...] 

這表明您事先知道表名。我可以設置知道每個表名的腳本，但是說我在路上添加一個新表，並忘記更新轉儲腳本。然後我缺少一個或多個表的轉儲。

有沒有辦法自動將每個現有錶轉儲到單獨的文件？或者我將不得不做一些腳本 - 福;查詢數據庫，獲取所有表名，並通過名稱轉儲它們。

如果我去腳本fu路由，什麼腳本語言可以訪問mysql數據庫？

Answer 1

mysqldump命令行程序會爲你做這件事 - 儘管the docs對此很不清楚。

需要注意的一件事是〜/ output/dir必須由擁有mysqld的用戶寫入。在Mac OS X：

sudo chown -R _mysqld:_mysqld ~/output/dir 
mysqldump --user=dbuser --password --tab=~/output/dir dbname 

運行以上後，您將有一個包含每個表的模式（create table語句），幷包含數據tablename.txt文件一個文件tablename.sql。

如果你想與模式的轉儲只，加上--no數據標誌：

mysqldump --user=dbuser --password --no-data --tab=~/output/dir dbname 

Answer 2

我不是bash高手，但我只是做一個bash腳本。如果不知道MySQL，只要知道數據目錄和數據庫名稱，就可以掃描所有.frm文件（該數據庫/目錄中的每個表的一個文件）以獲取表列表。

我敢肯定有辦法讓它變得更輕鬆，並接受參數或什麼，但這對我很好。

tables_in_a_db_to_sql.sh

#!/bin/bash 

database="this_is_my_database" 
datadir="/var/lib/mysql/" 
datadir_escaped="\/var\/lib\/mysql\/" 

all_tables=($(ls $datadir$database/*.frm | sed s/"$datadir_escaped$database\/"/""/g | sed s/.frm//g)) 

for t in "${all_tables[@]}"; do 
     outfile=$database.$t.sql 
     echo "-- backing up $t to $outfile" 
     echo "mysqldump [options] $database $t > $outfile" 
     # mysqldump [options] $database $t > $outfile 
done 

填寫的[選項]和所需OUTFILE慣例，因爲你需要，並取消了最後的mysqldump線。

Answer 3

你可以做到這一點：

1. 獲取mysql中
數據庫列表
2. 轉儲每個數據庫與mysqldump

# Optional variables for a backup script 
MYSQL_USER="root" 
MYSQL_PASS="something" 
BACKUP_DIR=/srv/backup/$(date +%Y-%m-%dT%H_%M_%S); 
test -d "$BACKUP_DIR" || mkdir -p "$BACKUP_DIR" 
# Get the database list, exclude information_schema 
for db in $(mysql -B -s -u $MYSQL_USER --password=$MYSQL_PASS -e 'show databases' | grep -v information_schema) 
do 
    # dump each database in a separate file 
    mysqldump -u $MYSQL_USER --password=$MYSQL_PASS "$db" | gzip > "$BACKUP_DIR/$db.sql.gz" 
done 

Answer 4

這是一個將表格數據作爲SQL命令轉儲爲單獨的壓縮文件的腳本。它不需要是MySQL服務器主機上，確實在劇本沒有硬編碼密碼，並且是隻爲特定分貝，而不是服務器上的所有數據庫的：

#!/bin/bash 

# dump-tables-mysql.sh 
# Descr: Dump MySQL table data into separate SQL files for a specified database. 
# Usage: Run without args for usage info. 
# Author: @Trutane 
# Ref: http://stackoverflow.com/q/3669121/138325 
# Notes: 
# * Script will prompt for password for db access. 
# * Output files are compressed and saved in the current working dir, unless DIR is 
# specified on command-line. 

[ $# -lt 3 ] && echo "Usage: $(basename $0) <DB_HOST> <DB_USER> <DB_NAME> [<DIR>]" && exit 1 

DB_host=$1 
DB_user=$2 
DB=$3 
DIR=$4 

[ -n "$DIR" ] || DIR=. 
test -d $DIR || mkdir -p $DIR 

echo -n "DB password: " 
read -s DB_pass 
echo 
echo "Dumping tables into separate SQL command files for database '$DB' into dir=$DIR" 

tbl_count=0 

for t in $(mysql -NBA -h $DB_host -u $DB_user -p$DB_pass -D $DB -e 'show tables') 
do 
    echo "DUMPING TABLE: $DB.$t" 
    mysqldump -h $DB_host -u $DB_user -p$DB_pass $DB $t | gzip > $DIR/$DB.$t.sql.gz 
    tbl_count=$((tbl_count + 1)) 
done 

echo "$tbl_count tables dumped from database '$DB' into dir=$DIR" 

Answer 5

下面是相應的進口。

#!/bin/bash 

# import-files-mysql.sh 
# Descr: Import separate SQL files for a specified database. 
# Usage: Run without args for usage info. 
# Author: Will Rubel 
# Notes: 
# * Script will prompt for password for db access. 

[ $# -lt 3 ] && echo "Usage: $(basename $0) <DB_HOST> <DB_USER> <DB_NAME> [<DIR>]" && exit 1 

DB_host=$1 
DB_user=$2 
DB=$3 
DIR=$4 

DIR=$DIR/* 


echo -n "DB password: " 
read -s DB_pass 
echo 
echo "Importing separate SQL command files for database '$DB' into '$DB'" 

file_count=0 


for f in $DIR 

do 
    echo "IMPORTING FILE: $f" 

    gunzip -c $f | mysql -h $DB_host -u $DB_user -p$DB_pass $DB 

    ((file_count++)) 
done 

echo "$file_count files importing to database '$DB'" 

Answer 6

見聖保利馬庫斯下面的文章：

Howto split a SQL database dump into table-wise files

Splitting a sql file containing a whole database into per-table files is quite easy: Grep the .sql for any occurence of DROP TABLE. Generate the file name from the table name that is included in the DROP TABLE statement. Echo the output to a file. Here is a little script that expects a .sql file as input:

#!/bin/bash 

file=$1 # the input file 
directory="$file-splitted" # the output directory 
output="$directory/header" # the first file containing the header 
GREP="DROP TABLE" # what we are looking for 

mkdir $directory # create the output directory 

while read line 
do 
    # if the current line contains the wanted statement 
    if [ $(echo "$line" | grep -c "$GREP") == "1" ] 
    then 
     # extract the file name 
     myfile=$(echo $line | awk '{print $5}' | sed -e 's/`//g' -e 's/;//g') 
     # set the new file name 
     output="$directory/$myfile" 
    fi 
     echo "$line" >> $output # write to file 
done < $file 

Answer 7

看樣子這裏每個人都忘了autocommit=0;SET unique_checks=0;SET foreign_key_checks=0;是想加快導入過程...

#!/bin/bash 
MYSQL_USER="USER" 
MYSQL_PASS="PASS" 

if [ -z "$1" ] 
    then 
    echo "Dumping all DB ... in separate files" 
    for I in $(mysql -u $MYSQL_USER --password=$MYSQL_PASS -e 'show databases' -s --skip-column-names); 
    do 
     echo "SET autocommit=0;SET unique_checks=0;SET foreign_key_checks=0;" > "$I.sql" 
     mysqldump -u $MYSQL_USER --password=$MYSQL_PASS $I >> "$I.sql"; 
     echo "SET autocommit=1;SET unique_checks=1;SET foreign_key_checks=1;commit;" >> "$I.sql" 
     gzip "$I.sql" 
    done 
    echo "END." 
else 
     echo "Dumping $1 ..." 
     echo "SET autocommit=0;SET unique_checks=0;SET foreign_key_checks=0;" > "$1.sql" 
     mysqldump -u $MYSQL_USER --password=$MYSQL_PASS $1 >> "$1.sql"; 
     echo "SET autocommit=1;SET unique_checks=1;SET foreign_key_checks=1;commit;" >> "$1.sql" 
     gzip "$1.sql" 
fi 

Answer 8

#!/bin/bash 

for i in $(mysql -uUser -pPASSWORD DATABASE -e "show tables;"|grep -v Tables_in_);do mysqldump -uUSER -pPASSWORD DATABASE $i > /backup/dir/$i".sql";done 

tar -cjf "backup_mysql_"$(date +'%Y%m%d')".tar.bz2" /backup/dir/*.sql