1件背景INF的：這是關於持有對象CMS - 客體關係及其在單表的排序，列OBJECT_ID，PARENT_ID和排序順序需要幫助與MySQL查詢

第二張有若干個連接查詢，我想按2個參數排序。其中一個是對象本身的排序，第二個是父對象的排序順序。

查詢我有現在是：

SELECT obj_asset.*, object.headline AS title, oo.sort_order AS sort, op.sort_order FROM obj_asset 
JOIN object ON obj_asset.object_id = object.object_id 
JOIN object_object AS oo on obj_asset.object_id = oo.object_id 
JOIN (SELECT sort_order from object_object WHERE object_id = (SELECT parent_id from object_object WHERE object_id = obj_asset.object_id)) AS op ON obj_asset.object_id = oo.object_id 
WHERE obj_asset.profile_id = 140 AND obj_asset.rsvp_enabled = 1 AND object.is_published = 1 ORDER BY sort DESC;

而且這是行不通的。這雖然能正常工作：

SELECT obj_asset.*, object.headline AS title, oo.sort_order AS sort, op.sort_order FROM obj_asset 
JOIN object ON obj_asset.object_id = object.object_id 
JOIN object_object AS oo on obj_asset.object_id = oo.object_id 
JOIN (SELECT sort_order from object_object WHERE object_id = (SELECT parent_id from object_object WHERE object_id = 11111)) AS op ON obj_asset.object_id = oo.object_id 
WHERE obj_asset.profile_id = 140 AND obj_asset.rsvp_enabled = 1 AND object.is_published = 1 ORDER BY sort DESC;

我得到的錯誤是：

1054 - 未知列'obj_asset.object_id 'where子句'

我怎樣才能得到它的工作？

謝謝！

編輯：我可以解決這個問題，如果我能想出替代方法來包括父母排序到查詢中。有沒有這樣的方式？

來源

2011-02-07 Odif Yltsaeb

你確定你已經在obj_asset表OBJECT_ID列？ – KomarSerjio 2011-02-07 21:12:58

錯誤信息在這個例子中是一個很好的線索。（如果解釋器嘗試使用錯誤的object_id字段，則可能必須使用`tablename.fieldname`命名樣式。）:-) – 2011-02-07 21:14:14

@KomarSerjio - 是的，我 - 你可以看到，它不是唯一的地方，我使用相同的列和表，它的工作原理，如果我改變它的實際ID。 @middaparka - 我明白爲什麼會出現錯誤 - 在內部選擇的上下文中，沒有obj_asset.object_id，因爲它尚未被選中......但是我怎樣才能解決這個只有一個查詢？ – 2011-02-07 21:18:00

正如你已經想通了，問題是，你正在嘗試在子查詢約束中使用外部查詢中的列：

(SELECT sort_order 
     from object_object 
     WHERE object_id = (SELECT parent_id 
         from object_object 
         WHERE object_id = obj_asset.object_id) 
    )

此子查詢可以重寫，b不知道如何只看你的原始查詢。

有可能是你的原始查詢錯誤（格式化）：

SELECT obj_asset.*, object.headline AS title, oo.sort_order AS sort, op.sort_order 
FROM obj_asset 
JOIN object ON obj_asset.object_id = object.object_id 
JOIN object_object AS oo on obj_asset.object_id = oo.object_id 
JOIN (SELECT sort_order 
     from object_object 
     WHERE object_id = (SELECT parent_id 
         from object_object 
         WHERE object_id = obj_asset.object_id) 
    ) AS op ON obj_asset.object_id = oo.object_id 
WHERE obj_asset.profile_id = 140 AND obj_asset.rsvp_enabled = 1 AND object.is_published = 1 ORDER BY sort DESC;

任何不使用名爲op子查詢中加入或where子句。

我最好的猜測是，你想以下幾點：

SELECT obj_asset.*, object.headline AS title, oo.sort_order AS sort, op.sort_order 
FROM obj_asset 
JOIN object ON obj_asset.object_id = object.object_id 
JOIN object_object AS oo on obj_asset.object_id = oo.object_id 
JOIN (SELECT sort_order, o2.object_id 
    from object_object as o1 
    INNER JOIN object_object as o2 ON o1.object_id = o2.parent_id 
    ) AS op ON obj_asset.object_id = op.object_id 
WHERE obj_asset.profile_id = 140 AND obj_asset.rsvp_enabled = 1 AND object.is_published = 1 ORDER BY sort DESC;

來源

2011-02-07 21:47:23 marapet

您的子查詢不在FROM子句中包含obj_asset。

(SELECT parent_id FROM object_object WHERE object_id = obj_asset.object_id)

讓這部分運行，你應該有更好的運氣與整個事情。

只是一個提示......如果你在你的SQL語句中添加更多的新行和縮進，你會更容易發現問題。

來源

2011-02-07 21:16:21 Nathan

meh？是的..我知道那是問題所在。我只是想不出有什麼辦法來修復它。 – 2011-02-07 21:25:07

我認爲你需要鍵入這個（包括obj_asset從）：

(SELECT parent_id FROM object_object, obj_asset WHERE object_object.object_id = obj_asset.object_id)

但不是這樣的：

(SELECT parent_id from object_object WHERE object_id = obj_asset.object_id)

來源

2011-02-07 21:20:22 SVGreg

需要幫助與MySQL查詢

1054 - 未知列'obj_asset.object_id 'where子句'

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