刪除陣列的給定鍵的元素在PHP

Question

$nesAry=array(); 
$nesAry["name"]="abc"; 
$nesAry["email"]="abc@email.com"; 

$nesAry1=array(); 
$nesAry1["name"]="abc1"; 
$nesAry1["email"]="abc1@email.com"; 

$nesAry2=array(); 
$nesAry2["name"]="abc2"; 
$nesAry2["email"]="abc2@email.com"; 


$responseAry = array(); 
$responseAry[0]=$nesAry; 
$responseAry[1]=$nesAry1; 
$responseAry[2]=$nesAry2; 


echo json_encode($responseAry); // here output like this => [{"name":"abc","email":"abc@email.com"},{"name":"abc1","email":"abc1@email.com"},{"name":"abc2","email":"abc2@email.com"}] 

unset($responseAry[1]); 

echo "------------removed 1--------"; 


echo json_encode($responseAry); // but here output like this => {"0":{"name":"abc","email":"abc@email.com"},"2":{"name":"abc2","email":"abc2@email.com"}} 

我想出來把篩選移除元素\ n [{「名」之後：「ABC」，「電子郵件」：「abc@email.com」 }，{ 「名」： 「ABC2」， 「電子郵件」： 「abc2@email.com」}]

請幫我

Answer 1

嘗試取消設置項後重新生成陣列：

$nesAry=array(); 
$nesAry["name"]="abc"; 
$nesAry["email"]="abc@email.com"; 

$nesAry1=array(); 
$nesAry1["name"]="abc1"; 
$nesAry1["email"]="abc1@email.com"; 

$nesAry2=array(); 
$nesAry2["name"]="abc2"; 
$nesAry2["email"]="abc2@email.com"; 


$responseAry = array(); 
$responseAry[0]=$nesAry; 
$responseAry[1]=$nesAry1; 
$responseAry[2]=$nesAry2; 


echo json_encode($responseAry); // __here output like this => [{"name":"abc","email":"abc2@email.com"},{"name":"abc1","email":"abc1@email.com"},{"name":"abc2"}]__ 

unset($responseAry[1]); 

$responseAry = array_values($responseAry); //regenerate array(reindexing) 

echo "------------removed 1--------"; 


echo json_encode($responseAry); //[{"name":"abc","email":"abc@email.com"},{"name":"abc2","email":"abc2@email.com"}] 

編輯：

至於其他選項，您可以使用array_splice方法http://php.net/manual/en/function.array-splice.php

$nesAry=array(); 
$nesAry["name"]="abc"; 
$nesAry["email"]="abc@email.com"; 

$nesAry1=array(); 
$nesAry1["name"]="abc1"; 
$nesAry1["email"]="abc1@email.com"; 

$nesAry2=array(); 
$nesAry2["name"]="abc2"; 
$nesAry2["email"]="abc2@email.com"; 


$responseAry = array(); 
$responseAry[0]=$nesAry; 
$responseAry[1]=$nesAry1; 
$responseAry[2]=$nesAry2; 


echo json_encode($responseAry); // __here output like this => [{"name":"abc","email":"abc2@email.com"},{"name":"abc1","email":"abc1@email.com"},{"name":"abc2"}]__ 

array_splice($responseAry,1,1); 
echo "------------removed 1--------"; 


echo json_encode($responseAry); 

Answer 2

你的數組時先轉換爲JSON是一種所謂的「聯想」的數組，並json_encode然後將其出口到你看到對象在第一個回聲中。

在您取消設置後，數組將更改爲「數字」數組，並且json_encode將使用數組鍵將數組導出。

Php它自己不關心數組是如何使用的，但json_encode的確如此。

您可以使用

echo json_encode(array_values($responseAry));

不改要導出