比較表中的記錄，並在SQL Server

Question

過濾他們的數據我有一個表，包括像下面的數據：

PersonalID | Date 

193  | 2017-06-01 08:02:00 
193  | 2017-06-01 08:03:00 
193  | 2017-06-01 08:03:00 
193  | 2017-06-01 08:04:00 
193  | 2017-06-01 08:09:00 
193  | 2017-06-01 09:01:00 
193  | 2017-06-01 09:06:00 
193  | 2017-06-01 09:08:00 

我想選擇的所有記錄，他們的時間差超過10分鐘大。

例如，根據這個數據我想，以顯示與日期 記錄「2017年6月1日8點02分00秒」 和 「2017年6月1日9點01分00秒」，而忽略其他記錄。

我可以通過不同的關鍵字忽略重複記錄（具有相同日期），但我不知道如何比較記錄並選擇日期差異大於10分鐘的記錄。

我使用此查詢來實現此目的，但它返回錯誤的記錄。

declare @space int = 10; 

with aaa as (select main.ID, main.PersonalID, main.Date 
from HZG_Traffic main 
where exists(select * from HZG_Traffic tr 
where tr.PersonalID = main.PersonalID and 
ABS(DATEDIFF(MI, main.Date,tr.Date)) < @space and 
ABS(DATEDIFF(MI, main.Date, tr.Date)) <> 0) 
and main.PersonalID = 193) 

Select * from aaa 
where id not in 
(select 
    MIN(ID) 
from aaa 
group by 
PersonalID, 
DATEPART(DAY, Date), DATEPART(MONTH, Date), DATEPART(YEAR, Date), 
DATEPART(HOUR, Date)) 
order by Date desc 

你能幫助我還是你有更好的想法解決這個問題？

感謝

UPDATE：

感謝的解決方案，我使用SQL Server 2014

Answer 1

假設你使用SQL Server 2012或更高版本，可以使用LAG & LEAD功能...

IF OBJECT_ID('tempdb..#TestData', 'U') IS NOT NULL 
DROP TABLE #TestData; 

CREATE TABLE #TestData (
    PersonalID INT NOT NULL, 
    SomeDate DATETIME2(0) NOT NULL 
    ); 
INSERT #TestData (PersonalID, SomeDate) VALUES 
    (193, '2017-06-01 08:02:00'), 
    (193, '2017-06-01 08:03:00'), 
    (193, '2017-06-01 08:03:00'), 
    (193, '2017-06-01 08:04:00'), 
    (193, '2017-06-01 08:09:00'), 
    (193, '2017-06-01 09:01:00'), 
    (193, '2017-06-01 09:06:00'), 
    (193, '2017-06-01 09:08:00'); 

-- SELECT * FROM #TestData td; 

--================================================== 

WITH 
    cte_LagLead AS (
     SELECT 
      td.PersonalID, td.SomeDate, 
      LagMins = ABS(DATEDIFF(MINUTE, td.SomeDate, LAG(td.SomeDate, 1, td.SomeDate) OVER (PARTITION BY td.PersonalID ORDER BY td.SomeDate))), 
      LeadMins = DATEDIFF(MINUTE, td.SomeDate, LEAD(td.SomeDate, 1, td.SomeDate) OVER (PARTITION BY td.PersonalID ORDER BY td.SomeDate)) 
     FROM 
      #TestData td 
     ) 
SELECT 
    ll.PersonalID, ll.SomeDate 
FROM 
    cte_LagLead ll 
WHERE 
    ll.LagMins > 10 
    OR 
    ll.LeadMins > 10; 

結果...

PersonalID SomeDate 
----------- --------------------------- 
193   2017-06-01 08:09:00 
193   2017-06-01 09:01:00 

Answer 2

它確實取決於您使用的是哪個版本的SQL Server。以下是兩種解決方案，一種可以與SQL Server 2012及更高版本一起使用，另一種可與SQL Server 2008及更高版本一起使用。

第一個是SQL 2008和更高：

/* Populating the temp table with the data */ 
DECLARE @HZG_Traffic TABLE 
(PersonalID INT,Date DATETIME); 

INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 09:08:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:02:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:03:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:03:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:04:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:09:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 09:01:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 09:06:00'); 

/* Start with a CTE to number each record for the PersonalID */ 
WITH main AS (
    SELECT 
     ROW_NUMBER() OVER(PARTITION BY ht.PersonalID ORDER BY ht.Date) AS Row_No 
     ,ht.PersonalID 
     ,ht.Date 
    FROM @HZG_Traffic AS ht 
    ) 
SELECT 
    main.PersonalID 
    ,main.Date 
FROM main 
/* Self-join to get the previous record */ 
LEFT JOIN main AS prev ON main.PersonalID = prev.PersonalID AND main.Row_No-1 = prev.Row_No 
/* Another self join to get the next record */ 
LEFT JOIN main AS nex ON main.PersonalID = nex.PersonalID AND main.Row_No+1 = nex.Row_No 
/* Have the OR clause so it will return both records */ 
WHERE 10 <= DATEDIFF(MINUTE, main.Date, nex.Date) 
OR 10 <= DATEDIFF(MINUTE, prev.Date,main.Date); 

這一次將與SQL 2012和工作都高：

/* Populating the temp table with the data */ 
DECLARE @HZG_Traffic TABLE 
(PersonalID INT,Date DATETIME); 

INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 09:08:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:02:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:03:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:03:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:04:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 08:09:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 09:01:00'); 
INSERT INTO @HZG_Traffic (PersonalID,Date) VALUES (193,'2017-06-01 09:06:00'); 

/* Start with a CTE to get the next and previous records */ 
WITH main AS (
SELECT 
    ht.PersonalID, ht.Date 
    ,LEAD(ht.Date) OVER(PARTITION BY ht.PersonalID ORDER BY ht.Date) AS Next_Date 
    ,LAG(ht.Date) OVER(PARTITION BY ht.PersonalID ORDER BY ht.Date) AS Prev_Date 
FROM @HZG_Traffic AS ht 
) 
SELECT 
    main.PersonalID 
    ,main.Date 
FROM main 
/* Have the OR clause so it will return both records */ 
WHERE 10 <= DATEDIFF(MINUTE, main.Date, main.Next_Date) 
OR 10 <= DATEDIFF(MINUTE, main.Prev_Date, main.Date); 

Answer 3

你說要2017-06-01 08:02:00.000和2017-06-01 09:01:00.000，如果是的話，你可以嘗試這樣的事情。

SELECT * 
FROM HZG_Traffic t1 
     CROSS APPLY ( 
      SELECT MIN([Date]) AS MinDate 
      FROM HZG_Traffic t2 
      WHERE t1.PersonalID = t2.PersonalID 
        AND DATEDIFF(Minute, t2.[Date], t1.[Date]) < 10) t2 
WHERE t1.[Date] = t2.MinDate 

SQL Fiddle Demo