1)AVE嘗試ave
而不是tapply
,並確保只有被應用過的興趣,即列列3,4,5,
roll <- function(x) rollmean(x, 5, fill = NA)
cbind(df[1:2], lapply(df[3:5], function(x) ave(x, df$index, FUN = roll)))
,並提供:
date index x y z
1 2015-02-01 a NA NA NA
2 2015-02-02 a NA NA NA
3 2015-02-03 a 66.50522 127.45650 129.8472
4 2015-02-04 a 61.71320 123.83633 129.7673
5 2015-02-05 a 56.56125 120.86158 126.1371
6 2015-02-06 a 66.13340 119.93428 127.1819
7 2015-02-07 a 59.56807 105.83208 125.1244
8 2015-02-08 a 49.98779 95.66024 139.2321
9 2015-02-09 a NA NA NA
10 2015-02-10 a NA NA NA
11 2015-02-01 b NA NA NA
12 2015-02-02 b NA NA NA
13 2015-02-03 b 55.71327 117.52219 139.3961
14 2015-02-04 b 54.58450 107.81763 142.6101
15 2015-02-05 b 50.48102 104.94084 136.3167
16 2015-02-06 b 37.89790 95.45489 135.4044
17 2015-02-07 b 33.05259 85.90916 150.8673
18 2015-02-08 b 49.91385 90.04940 147.1376
19 2015-02-09 b NA NA NA
20 2015-02-10 b NA NA NA
2)通過另一種方法是使用by
。 roll2
處理一個組,by
將它應用於產生by
列表的每個組,並將do.call("rbind", ...)
放回到一起。
roll2 <- function(x) cbind(x[1:2], rollmean(x[3:5], 5, fill = NA))
do.call("rbind", by(df, df$index, roll2))
,並提供:
date index x y z
a.1 2015-02-01 a NA NA NA
a.2 2015-02-02 a NA NA NA
a.3 2015-02-03 a 66.50522 127.45650 129.8472
a.4 2015-02-04 a 61.71320 123.83633 129.7673
a.5 2015-02-05 a 56.56125 120.86158 126.1371
a.6 2015-02-06 a 66.13340 119.93428 127.1819
a.7 2015-02-07 a 59.56807 105.83208 125.1244
a.8 2015-02-08 a 49.98779 95.66024 139.2321
a.9 2015-02-09 a NA NA NA
a.10 2015-02-10 a NA NA NA
b.11 2015-02-01 b NA NA NA
b.12 2015-02-02 b NA NA NA
b.13 2015-02-03 b 55.71327 117.52219 139.3961
b.14 2015-02-04 b 54.58450 107.81763 142.6101
b.15 2015-02-05 b 50.48102 104.94084 136.3167
b.16 2015-02-06 b 37.89790 95.45489 135.4044
b.17 2015-02-07 b 33.05259 85.90916 150.8673
b.18 2015-02-08 b 49.91385 90.04940 147.1376
b.19 2015-02-09 b NA NA NA
b.20 2015-02-10 b NA NA NA
3)寬的形式另一種方法是從df
長形式轉換到寬形式在這種情況下一個普通的rollmean
將做到這一點。
rollmean(read.zoo(df, split = 2), 5, fill = NA)
,並提供:
x.a y.a z.a x.b y.b z.b
2015-02-01 NA NA NA NA NA NA
2015-02-02 NA NA NA NA NA NA
2015-02-03 66.50522 127.45650 129.8472 55.71327 117.52219 139.3961
2015-02-04 61.71320 123.83633 129.7673 54.58450 107.81763 142.6101
2015-02-05 56.56125 120.86158 126.1371 50.48102 104.94084 136.3167
2015-02-06 66.13340 119.93428 127.1819 37.89790 95.45489 135.4044
2015-02-07 59.56807 105.83208 125.1244 33.05259 85.90916 150.8673
2015-02-08 49.98779 95.66024 139.2321 49.91385 90.04940 147.1376
2015-02-09 NA NA NA NA NA NA
2015-02-10 NA NA NA NA NA NA
這工作,因爲日期是兩組相同。如果日期不同,那麼它可能會引入NAs,並且rollmean
無法處理這些問題。在這種情況下使用
rollapply(read.zoo(df, split = 2), 5, mean, fill = NA)
注:由於輸入使用隨機數在其定義,使其重現性,我們必須首先發出set.seed
。我們用這個:
set.seed(123)
date <- as.Date(c("2015-02-01", "2015-02-02", "2015-02-03", "2015-02-04",
"2015-02-05", "2015-02-06", "2015-02-07", "2015-02-08",
"2015-02-09", "2015-02-10", "2015-02-01", "2015-02-02",
"2015-02-03", "2015-02-04", "2015-02-05", "2015-02-06",
"2015-02-07", "2015-02-08", "2015-02-09", "2015-02-10"))
index <- c("a","a","a","a","a","a","a","a","a","a",
"b","b","b","b","b","b","b","b","b","b")
x <- runif(20,1,100)
y <- runif(20,50,150)
z <- runif(20,100,200)