2010-05-04 32 views
0

我想在圖像名稱爲查詢字符串的jqgrid的列中顯示圖像鏈接。鏈接應包含以下路徑「Home \ ShowImage?imageName = vlaue」。jqgrid列中的圖像鏈接

回答

0

您可以在URL參數通過XML或JSON移動圖像是這樣的:

$image = "<a href='#'><img src='folders/images/arrow.jpg' border='0' valign='middle' title='Edit something'><a>"; 



    echo "<?xml version='1.0' encoding='iso-8859-1'?$et\n"; 
    echo "<rows>"; echo "<page>".$page."</page>"; 
    echo "<total>".$total_pages."</total>"; 
    echo "<records>".$count."</records>"; // be sure to put text data in CDATA 

     echo "<row id='". $id."'>"; 
     echo "<cell>". $image."</cell>"; 
     echo "</row>"; 
     } 
    echo "</rows>"; 

請注意,應寫爲<一>