調用一個函數會讓我的代碼變得很慢

Question

我試圖實現一個給定矩形和由用戶決定的多個多邊形的算法，它可以識別它們是在裏面，外面還是相交矩形，並提供所述多邊形。我編碼算法，它的工作原理，但我注意到編譯後，它至少需要20秒啓動（如果我第二次，第三次或任何其他時間啓動它，這不會發生）。

試圖弄清楚我的代碼太慢了什麼，我注意到如果我刪除調用函數來確定多邊形相對於矩形的位置，程序立即運行。

我試圖找到一些錯誤，但沒有發現任何

這

// struct used in the function 
struct Polygon 
{ 
    int ** points; 
    int vertices; 
}; 
// inside, outside and over are the number of polygons that are inside, outside or intersect the rectangle, 
// they're initialized to 0 in the main. 
// down_side, up_side are the y_coordinate of the two horizontals sides. 
// left_side, right_side are the x_coordinate of the two vertical sides. 
void checkPolygons(Polygon * polygon, int & inside, int & outside, int & over, unsigned int polygons, const unsigned int down_side, const unsigned int up_side, const unsigned int left_side, const unsigned int right_side) 
{ 
    for (unsigned int pol = 0; pol < polygons; ++pol) 
    { 
     unsigned int insideVertices = 0; 
     unsigned int vertices = polygon[ pol ].vertices; 

     for (unsigned int point = 0; point < vertices; ++point) 
     { 
      unsigned int x_coordinate = polygon[ pol ].points[ point ][ 0 ]; 
      unsigned int y_coordinate = polygon[ pol ].points[ point ][ 1 ]; 

      if ((x_coordinate <= right_side) and (x_coordinate >= left_side) and (y_coordinate <= up_side) and (y_coordinate >= down_side)) 
      { 
       insideVertices++; 
      } 

     } 

     if (insideVertices == 0) 
      ++outside; 
     else if (insideVertices == vertices) 
      ++inside; 
     else 
      ++over; 
    } 
} 

Answer 1

檢查你的抗病毒活性和配置。它可能正在掃描新編譯的可執行文件中的病毒。如果是這種情況，您可能希望從病毒掃描中排除您編譯的目錄。