獲取數據庫表中的行的最大值

Question

我需要編寫一個SQL查詢，它將從表中獲取具有文件最大值的那些行。

數據庫表如下：

> ID status dept files 
> 
> > 1 1 23 1256637314 
> > 
> > 1 1 39 1256642968 
> > 
> > 2 0 85 1256551419 
> > 
> > 2 1 90 1256642968 
> > 
> > 2 1 93 1256810937 
> > 
> > 3 0 20 1256642968 
> > 
> > 5 1 342 1256810937 

現在從這個表我想那些具有最大文件由ID分組行：

> ID status dept files 
> 
> 1 1 39 1256642968 
> 
> 2 1 93 1256810937 
> 
> 3 0 20 1256642968 
> 
> 5 1 342 1256810937 

任何建議？

謝謝。

我試過，但這樣是不對的

Select ID, Status, dept,files 
from SLAStat 
where files in (Select Max(files) from SLAStat group by ID) 




2 1 90 1256642968 
1 1 39 1256642968 
3 0 20 1256642968 
5 1 342 1256810937 
2 1 93 1256810937 

Answer 1

通過你的表替換@ T1：

With idT as (
    select ID 
    from @t1 
    group by id 
) 
select applyT.* 
from idT p 
CROSS APPLY (
    select top 1 * from @t1 where ID=p.ID order by files desc 
) as applyT 

Answer 2

SELECT DISTINCT a.ID, a.Status, a.Dept, a.Files 
FROM table a 
INNER JOIN (
SELECT ID, MAX(files) AS Files 
FROM table 
GROUP BY ID) b ON a.ID = b.ID AND a.Files = b.Files 

Answer 3

SELECT MAX(files) as max_files, id, status, dept 
FROM table 
GROUP BY id 

Answer 4

我可能是過度簡化的問題，而是：

select top 5 * from SLAStat order by files desc;