在Textview中獲取響應，Url和Url代碼

Question

我正在嘗試向url發送一個請求並獲取顯示在TextView中的URL，響應代碼和響應。我能夠在日誌中獲取URL和響應代碼，但無法獲得響應。 請檢查代碼，並告訴如何讓所有的三個被印刷在TextView 感謝

import java.io.BufferedReader; 
import java.io.DataOutputStream; 
import java.io.InputStreamReader; 
import java.net.HttpURLConnection; 
import java.net.URL; 
import android.app.Activity; 
import android.os.AsyncTask; 
import android.os.Bundle; 
import android.widget.TextView; 
public class MainActivity extends Activity { 

String rescode,urlcode,responsecode; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    new LongOperation().execute(""); 
} 

private class LongOperation extends AsyncTask<String, Void, String> { 

    @Override 
    protected String doInBackground(String... params) { 
     try { 
      String url = "http://google.com"; 
      URL obj = new URL(url); 
      HttpURLConnection con = (HttpURLConnection) obj 
        .openConnection(); 



      // Send post request 
      con.setDoOutput(true); 
      DataOutputStream wr = new DataOutputStream(
        con.getOutputStream()); 

      wr.flush(); 
      wr.close(); 

      int responseCode = con.getResponseCode(); 

     //////////////////////////////////////////////////////////////// 
      /*TextView tv2 = (TextView) findViewById(R.id.textView2); 
      TextView tv3 = (TextView) findViewById(R.id.textView3); 

      urlcode = url.getBytes().toString(); 
      rescode = responsecode.getBytes().toString(); 

      tv2.getText().toString(); 
      tv2.setText("URL- "+urlcode); 
      tv3.setText("ResponseCode- "+rescode);*/ 

     /////////////////////////////////////////////////////////////////// 


      System.out.println("\nSending 'POST' request to URL : -----------------------" + url); 
    //  System.out.println("Post parameters : " + urlParameters); 
      System.out.println("Response Code : -------------------------------" + responseCode); 


      BufferedReader in = new BufferedReader(new InputStreamReader(
        con.getInputStream())); 
      String inputLine; 
      StringBuffer response = new StringBuffer(); 

      while ((inputLine = in.readLine()) != null) { 
       response.append(inputLine); 
      } 
      in.close(); 

      // print result 
      System.out.println("+++++++++"+response.toString()); 
     // System.out.println("Response" +response); 
      TextView tv = (TextView) findViewById(R.id.textView1); 
      rescode = response.toString(); 

      tv.setText("aa"+rescode); 
      return response.toString(); 

     } catch (Exception e) { 
      System.out 
        .println("MainActivity.LongOperation.doInBackground()"+e); 

     } 
     return null; 

    } 

    @Override 
    protected void onPostExecute(String result) { 

    } 

    @Override 
    protected void onPreExecute() { 
    } 

    @Override 
    protected void onProgressUpdate(Void... values) { 
    } 
} 
} 

登錄

05-09 16:09:59.642: I/System.out(16309): Sending 'POST' request to URL : ---------------http://google.com 

05-09 16:09:59.652: I/System.out(16309): Response Code : ------------------------------405 

    050916:09:59.652:I/System.out(16309):MainActivity.LongOperation.doInBackground()java.io.FileNotFoundException: http://google.com 

Answer 1

不要doInBackground方法來訪問UI

請嘗試以下

private class LongOperation extends AsyncTask<String, Void, String> { 

@Override 
protected String doInBackground(String... params) { 
    try { 
     String url = "http://google.com"; 
     URL obj = new URL(url); 
     HttpURLConnection con = (HttpURLConnection) obj 
       .openConnection(); 



     // Send post request 
     con.setDoOutput(true); 
     DataOutputStream wr = new DataOutputStream(
       con.getOutputStream()); 

     wr.flush(); 
     wr.close(); 

     int responseCode = con.getResponseCode(); 

    //////////////////////////////////////////////////////////////// 
     /*TextView tv2 = (TextView) findViewById(R.id.textView2); 
     TextView tv3 = (TextView) findViewById(R.id.textView3); 

     urlcode = url.getBytes().toString(); 
     rescode = responsecode.getBytes().toString(); 

     tv2.getText().toString(); 
     tv2.setText("URL- "+urlcode); 
     tv3.setText("ResponseCode- "+rescode);*/ 

    /////////////////////////////////////////////////////////////////// 


     System.out.println("\nSending 'POST' request to URL : -----------------------" + url); 
//  System.out.println("Post parameters : " + urlParameters); 
     System.out.println("Response Code : -------------------------------" + responseCode); 


     BufferedReader in = new BufferedReader(new InputStreamReader(
       con.getInputStream())); 
     String inputLine; 
     StringBuffer response = new StringBuffer(); 
     if(in!=null){ 
      while ((inputLine = in.readLine()) != null) { 
      response.append(inputLine); 
      } 
     in.close(); 
     } 

     // print result 
     System.out.println("+++++++++"+response.toString()); 
    // System.out.println("Response" +response); 

     rescode = response.toString(); 


     return response.toString(); 

    } catch (Exception e) { 
     System.out 
       .println("MainActivity.LongOperation.doInBackground()"+e); 

    } 
    return null; 

} 

@Override 
protected void onPostExecute(String result) { 
    tv.setText("aa"+result); 
} 

@Override 
protected void onPreExecute() { 
} 

@Override 
protected void onProgressUpdate(Void... values) { 
} 
} 
}