2017-08-07 50 views
-1

所以我有以下的JSON。我在尋找的結果是,如果有多個對象具有相同的site_id,要創建一個包含site_id,用戶數組和其餘屬性合併在一起的對象。 我試着使用減少,但它不工作:d如何合併多個對象與JavaScript中的數組類似的鍵

預先感謝您

{ 
     "response": [ 
      { 
       "site_id": "4587c4183c312dd82309be6cdae7bbd6", 
       "name": "esse", 
       "lat": 82.3172, 
       "lon": -30.0668, 
       "company": "256090f4d3a41f34096876b71ee03694", 
       "user_id": "2d3393051386426adca86c13362e6f46", 
       "UserName": "Juliet44", 
       "Password": "Test", 
       "FirstName": "Kristy", 
       "LastName": "Goldner", 
       "Company": "256090f4d3a41f34096876b71ee03694", 
       "Email": "[email protected]", 

      }, 
      { 
       "site_id": "4587c4183c312dd82309be6cdae7bbd6", 
       "lat": 82.3172, 
       "lon": -30.0668, 
       "company": "256090f4d3a41f34096876b71ee03694", 
       "user_id": "2f2a174f63f7e277630eb808974dfd05", 
       "UserName": "Marguerite_Smith34", 
       "Password": "Test", 
       "FirstName": "Christian", 
       "LastName": "Gerhold", 
       "Company": "256090f4d3a41f34096876b71ee03694", 
       "Email": "[email protected]", 
      }, 
      { 
       "site_id": "94fc61eee3c0d01abace7a2feb84bc4c", 
       "name": "blanditiis", 
       "lat": 13.3673, 
       "lon": 54.3085, 
       "company": "256090f4d3a41f34096876b71ee03694", 
       "user_id": "3f85f1a435df6c3ca4ac944116515c04", 
       "UserName": "Tyrell.Schimmel", 
       "Password": "Test", 
       "FirstName": "Lucius", 
       "LastName": "O'Conner", 
       "Company": "256090f4d3a41f34096876b71ee03694", 
       "Email": "[email protected]", 
      }, 
     ] 
    } 
+2

*「我試過使用減少」* ...顯示你的嘗試。 Stackoverflow不是免費的代碼寫入服務。這裏的目標是幫助你解決**你的代碼**。請花一些時間閱讀[ask] – charlietfl

+0

你能顯示你想要的輸出嗎 –

+0

'site_id','Company'和'company'有什麼區別? – Andy

回答

0

也許剩下的操作是你的朋友。我不確定如果你真的需要減少,一個簡單的forEach它:

var hash={}, result = []; 

response.forEach(function({site_id,...rest}){ 
    if(!hash[site_id]){ 
    result.push(hash[site_id]={site_id}); 
    } 
    let el = hash[site_id]; 
    for(key in rest){ 
    if(el[key]){ 
     el[key].push(rest[key]); 
    }else{ 
     el[key] = [rest[key]]; 
    } 
    } 
}); 
+0

是的,這是完美的作品,我設法解決你的問題。謝謝 –

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