Swift更復雜的數組字典

Question

我想要統計一個人在一天中喝一杯水的時間（一個小時的時間間隔內）的次數，我無法確定如何正確構建這個數據結構，預期數據將是這個樣子：

day1 = [hour interval: [time, time, time], hour interval: [time], hour interval: [time], hour:[time]] 

它打印出一個空數組......到目前爲止，我有這樣的：

var counts = [String:Array<NSDate>]() 
var dict = [[NSDate:Array<[String:Array<NSDate>]>]]() 

//datesArray -> is an array of dates from something like monday to friday 
/* 
datesArray: 

2016-07-23 
2016-07-24 
2016-07-25 
2016-07-26 
2016-07-27 
2016-07-28 
2016-07-29 
2016-07-30 
*/ 


    for date in datesArray { 

      //tempDoses has the times when the user took the glass of water 
/* 
tempDoses: 

2016-07-28 23:50:50 +0000 
2016-07-26 13:06:57 +0000 
2016-07-25 08:47:52 +0000 
2016-07-25 08:46:47 +0000 
2016-07-25 08:46:06 +0000 
2016-07-24 23:25:07 +0000 
2016-07-24 14:18:11 +0000 
2016-07-24 13:58:35 +0000 
2016-07-22 09:10:59 +0000 
2016-07-22 09:10:26 +0000 
2016-07-22 09:09:28 +0000 
*/ 


       for temp in tempDoses { 

        if calendar.isDate(date, inSameDayAsDate: temp.logTime) 



         let dateformatter = NSDateFormatter() 

         dateformatter.dateFormat = "HH:mm" 

         let myDate = dateformatter.stringFromDate(temp.logTime) 



         let h = self.getHour(myDate) 

         for m in counts { 
         var o = m 

          if o.0 == h { 
           o.1.append(temp.logTime) 
          } 
         } 
        } 
       } 

       if counts.count > 0 { 
        dict.append([date:[counts]]) 
        counts.removeAll() 
       }else{ 
        dict.append([date:[]]) 
       } 
      } 

預期結果：

2016-07-21 = [] 
    2016-07-22 = ["10": [09:10, 09:13]] 
    2016-07-23 = [] 
    2016-07-24 = ["15": [14:18], "14": [13:12, 13:56]] 
    2016-07-25 = ["09": [08:33, 08:40], "00": [23:10]] 
    2016-07-26 = ["14": [13:33]] 
    2016-07-27 = [] 
    2016-07-28 = [] 

Answer 1

您的預期輸出與您的輸入不符！例如，在2016-07-22：

// Input 
2016-07-22 09:10:59 +0000 
2016-07-22 09:10:26 +0000 
2016-07-22 09:09:28 +0000 

// My expected output 
2016-07-22 = [9: ["09:10", "09:09"]] 

// Your expected output: 
2016-07-22 = ["10": [09:10, 09:13]] 

玩弄下面的代碼，直到你得到你想要的東西。 要特別注意的時區，因爲它是在與NSDate處理錯誤的主要來源：

let timeZone = NSTimeZone(forSecondsFromGMT: 0) 

let calendar = NSCalendar.currentCalendar() 
calendar.timeZone = timeZone 

let formatter = NSDateFormatter() 
formatter.dateFormat = "HH:mm" 
formatter.timeZone = timeZone 

var dict = [NSDate : [Int: [String]]]() 

for date in datesArray { 
    let dailyDoses = doses 
         .filter { calendar.startOfDayForDate($0.logTime) == date } 
         .sort { $0.logTime.timeIntervalSince1970 < $1.logTime.timeIntervalSince1970 } 

    dict[date] = [Int: [String]]() 

    dailyDoses.forEach { 
     let hour = calendar.component(.Hour, fromDate: $0.logTime) 
     let str = formatter.stringFromDate($0.logTime) 

     if dict[date]![hour] == nil { 
      dict[date]![hour] = [String]() 
     } 
     if !(dict[date]![hour]!.contains { $0 == str }) { 
      dict[date]![hour]!.append(str) 
     } 
    } 
} 

// Print the result 
for date in datesArray { 
    print(date, "=", dict[date]!) 
} 

/* Output: 
2016-07-22 00:00:00 +0000 = [9: ["09:09", "09:10"]] 
2016-07-23 00:00:00 +0000 = [:] 
2016-07-24 00:00:00 +0000 = [14: ["14:18"], 23: ["23:25"], 13: ["13:58"]] 
2016-07-25 00:00:00 +0000 = [8: ["08:46", "08:47"]] 
2016-07-26 00:00:00 +0000 = [13: ["13:06"]] 
2016-07-27 00:00:00 +0000 = [:] 
2016-07-28 00:00:00 +0000 = [23: ["23:50"]] 
*/