更改Json輸出

如何從數據庫生成此輸出。我使用PHP和MySQL，並希望此輸出在此格式下使用JSON更改Json輸出

但我輸出

{"earthquakes": [ 
    { 
     "eqid": "c0001xgp", 
     "magnitude": 8.8, 
     "lng": 142.369, 
     "src": "us", 
     "datetime": "2011-03-11 04:46:23", 
     "depth": 24.4, 
     "lat": 38.322 
    }, 
    { 
     "eqid": "2007hear", 
     "magnitude": 8.4, 
     "lng": 101.3815, 
     "src": "us", 
     "datetime": "2007-09-12 09:10:26", 
     "depth": 30, 
     "lat": -4.5172 
    } 
<--more --> 
]}

所以請指導我如何更新我的代碼？

我設置這一點，因爲我想，以適應它的Android應用程序，其代碼

package com.pxr.tutorial.json; 

import java.util.ArrayList; 
import java.util.HashMap; 

import org.json.JSONArray; 
import org.json.JSONException; 
import org.json.JSONObject; 
import org.w3c.dom.Document; 
import org.w3c.dom.Element; 
import org.w3c.dom.NodeList; 

import com.pxr.tutorial.xmltest.R; 

import android.app.ListActivity; 
import android.content.Intent; 
import android.os.Bundle; 
import android.util.Log; 
import android.view.View; 
import android.widget.AdapterView; 
import android.widget.AdapterView.OnItemClickListener; 
import android.widget.ListAdapter; 
import android.widget.ListView; 
import android.widget.SimpleAdapter; 
import android.widget.Toast; 

public class Main extends ListActivity { 
    /** Called when the activity is first created. */ 
    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.listplaceholder); 

     ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>(); 


     JSONObject json = JSONfunctions.getJSONfromURL("http://midsweden.gofreeserve.com/fetch.php"); 

     try{ 

      JSONArray earthquakes = json.getJSONArray("earthquakes"); 

      for(int i=0;i<earthquakes.length();i++){       
       HashMap<String, String> map = new HashMap<String, String>();  
       JSONObject e = earthquakes.getJSONObject(i); 

       map.put("id", String.valueOf(i)); 
       map.put("name", "Earthquake name:" + e.getString("eqid")); 
       map.put("magnitude", "Magnitude: " + e.getString("magnitude")); 
       mylist.add(map);    
      }  
     }catch(JSONException e)  { 
      Log.e("log_tag", "Error parsing data "+e.toString()); 
     } 

     ListAdapter adapter = new SimpleAdapter(this, mylist , R.layout.main, 
         new String[] { "name", "magnitude" }, 
         new int[] { R.id.item_title, R.id.item_subtitle }); 

     setListAdapter(adapter); 

     final ListView lv = getListView(); 
     lv.setTextFilterEnabled(true); 
     lv.setOnItemClickListener(new OnItemClickListener() { 
      public void onItemClick(AdapterView<?> parent, View view, int position, long id) {    
       @SuppressWarnings("unchecked") 
       HashMap<String, String> o = (HashMap<String, String>) lv.getItemAtPosition(position);     
       Toast.makeText(Main.this, "ID '" + o.get("id") + "' was clicked.", Toast.LENGTH_SHORT).show(); 

      } 
     }); 
    } 
}

感謝

來源

2011-04-28 umar

你爲什麼需要它格式化？ – 2011-04-28 18:33:10

我有Android的代碼，這種格式的過程，所以我想適合它 – umar 2011-04-28 18:38:10

爲什麼不使用JSON解析器：http：//developer.android.com/reference/org/json/package-summary.html你的android應用程序？ – 2011-04-28 18:39:51

所有我需要的是這些集線

$rs = mysql_query("SELECT * FROM earthquakes"); 

    while($obj = mysql_fetch_object($rs)) { 
      $arr[] = $obj; 
     } 

     echo '{"earthquakes":'.json_encode($arr).'}'

;

來源

2011-04-28 21:08:16 umar

更好：'echo json_encode（array（'地震'=> $ arr））;' – 2011-04-28 21:29:44

更改Json輸出

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