如何去除Java字符串中的大括號？

Question

我的Java應用程序將會得到如下形式的字符串：

How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan. 

，需要一個正則表達式/方法，將剝離出的[[ ]]每個實例（和全包文本），從而把上面的字符串爲：

How now. The arsonist feet. The a bank loan. 

聲明保留的雙空格（arsonist和feet，與和之間Thea之間）？這也很重要。

不確定這裏的正則表達式是否合適，或者是否有更有效的方法剔除不需要的[[ ]]實例。

Answer 1

這是javascript。

var text = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan." 
text.replace(/\[\[[^\]]+\]\]/g, "") 

要匹配的正則表達式的括號將

/\[\[[^\]]+\]\]/g 

所以相當於Java將是

text.replaceAll("\[\[[^\]]+\]\]", ""); 

，並用一個空字符串

正則表達式，可以刪除這兩個更換雙重和三重大括號

text.replaceAll("\[?\[\[[^\]]+\]\]\]?", "") 

Answer 2

這是replaceAll

str = str.replaceAll("\\[\\[[^\\]]*\\]\\]", ""); 

簡單假設括號之間沒有]。

Answer 3

嘗試使用此代碼：

public class Test{ 
public static void main(String[] args) { 
    String input = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan."; 
    // Will replace all data within braces [] 
    String replaceAll = input.replaceAll("(\\[.+?\\])|(\\])", ""); 
    System.out.println(replaceAll); 
} 

}

希望這有助於。

Answer 4

tring s = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan."; 

s=s.replaceAll("\\[.*?\\]","").replace("]",""); 

輸出：

How now . The arsonist feet. The a bank loan.