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我正在嘗試將一個嵌套列表拼合成一個列表並刪除所有Nones。但是當有多個無時,總是有一個無剩餘。也有時我有一個None作爲一個int類型(如在第一個列表李第二無)什麼?哈哈。請幫助我,並提前致謝。無法從列表中刪除NoneTypes(python)
#test lists--li is the orignal one provided by Button
li = [0, 2, [[2, 3], 8, 100, None, [[None]]], -2]
li1 = [-100, -100, [[[None,None]]]]
li2 = [[[[[None,None,1,2,3]]]], 6, 0, 0, 0]
li3 = [None, [None], 56, 78, None]
li4 = [[[[[None,1,2,3]]]], 6, 0, 0, 0]
#solution is theta(n) or more specifically O(n)
#which is the best case solution since we must
#loop the entire list
def flatten(li):
i = 0
while i < len(li):
#only execute if the element is a list
while isinstance(li[i], list):
#taking the element at index i and sets it as the
#i'th part of the list. so if l[i] contains a list
#it is then unrolled or 'unlisted'
li[i:i + 1] = li[i]
i += 1
#for li: for some reason the 2nd None at
#index 7 is an int, probably because there
#might've been an int at that index before manipulation?
#for li1: the 2nd None or element at index 3
#is of class 'NoneType' but the removal is not
#occuring..
for element in li:
if element is None:
li.remove(element)
#conclusion: there is always one None remaining if
#there is more than one None to begin with..
return li
def main():
flatten(li)
print(li)
flatten(li1)
print(li1)
flatten(li2)
print(li2)
flatten(li3)
print(li3)
flatten(li4)
print(li4)
if __name__ == '__main__':
main()
_None爲int type_您可以將其輸出到列表 - 你是什麼意思? – DyZ
不要嘗試從列表中刪除項目,同時迭代它。建立一個只包含你想要的項目的新列表要容易得多。 – roganjosh
非常感謝roganjosh! –