這段代碼中的錯誤是什麼？

Question

void main (void) 
{ 
    char name [2] [30], number [2] [10]; 
    char << "Please type your first name, a blank, and last name) << endl; 
    cin >> name; 
    cout << "Name=" <<name << endl; 
    cout << "Please type a number, press the return key, and another number << endl; 
    cin >> number [0] >> endl; 
    cout << number << endl; 
} 

Answer 1

太多提及，但我們不是在這裏充當家庭作業服務。檢查你的編譯器的輸出，那麼解決這些問題一次一個：

---

qq.cpp:4:13: warning: missing terminating " character 
qq.cpp:4: error: missing terminating " character 
qq.cpp:7:13: warning: missing terminating " character 
qq.cpp:7: error: missing terminating " character 
qq.cpp:1: error: ‘::main’ must return ‘int’ 
qq.cpp: In function ‘int main()’: 
qq.cpp:4: error: expected unqualified-id before ‘<<’ token 
qq.cpp:6: error: ‘cout’ was not declared in this scope 
qq.cpp:6: error: ‘endl’ was not declared in this scope 
qq.cpp:8: error: ‘cin’ was not declared in this scope 

---

在最低限度：

• 沒有using條款或std::前綴。
• char不是流。
• 對某些字符串文字沒有關閉引號。

Answer 2

有在"Please type your first name, a blank, and last name)

Answer 3

末括號，而不是一個雙引號你不結束與「在

char << "Please type your first name, a blank, and last name) << endl; 

和

cout << "Please type a number, press the return key, and another number << endl; 

字符串

它應該是：

int main (void) 
{ 
char name [2] [30], number [2] [10]; 
char << "Please type your first name, a blank, and last name)" << endl; 
cin >> name; 
cout << "Name=" <<name << endl; 
cout << "Please type a number, press the return key, and another number" << endl; 
cin >> number [0] >> endl; 
cout << number << endl; 
return 0; 
} 

Answer 4

char << "Please type your first name, a blank, and last name) << endl; 

和

cout << "Please type a number, press the return key, and another number << endl; 

都缺少結束雙引號

char << "Please type your first name, a blank, and last name)" << endl; 
cout << "Please type a number, press the return key, and another number" << endl