2016-07-26 45 views
6

我想在這行中加入condition_variable處理線程,卻得到了一個編譯錯誤:編譯錯誤:「這個」不能在此背景下隱含捕獲

this->cv.wait(lk, []{return this->ready;}); 

貌似爲變量此 - >準備好了,'這'不在正確的範圍內。

在Java中,這可以用TestThread.this來處理,C++中是否還有相同的功能?

void TestThread::Thread_Activity() 
    { 
     std::cout << "Thread started \n"; 
     // Wait until ThreadA() sends data 
     { 
      std::unique_lock<std::mutex> lk(m); 
      this->cv.wait(lk, []{return ready;}); 
     } 

     std::cout << "Thread is processing data\n"; 
     data += " after processing"; 
     // Send data back to ThreadA through the condition variable 
     { 
      // std::lock_guard<std::mutex> lk(m); 
      processed = true; 
      // std::cout << "Thread B signals data processing completed\n"; 
     } 

    } 
+4

只需閱讀文檔lambda表達式...或者閱讀編譯錯誤,對於這個問題! –

回答

14

您需要捕獲this指針:

this->cv.wait(lk, [this]{return ready;});