2017-09-01 429 views
0

我發現solution通過Windows命令行直接從環境變量PATH中刪除某個目錄。但我想通過從cmd文件中發出命令來達到相同的結果。使用cmd文件從PATH中刪除不需要的目錄

什麼我能做的就是呼應我想PATH設置爲結果,如果我把

echo %PATH:D:\dir-path;=% 

到我的CMD文件。但如果我寫

set PATH=%PATH:D:\dir-path;=% 

PATH只包含我想要刪除的目錄。

此外,我想爲導演路徑使用一個變量,但如果我嘗試結果更糟。我把

set dirPath=D:\dir-path 
echo %PATH:%dirPath%;=% 

和我所得到的全部是dirPath;=

我不知道如何解決這個問題,所以如果有人能夠協助我會很感激。

編輯1

正如@Anders建議我現在有:

@echo off 

set exampleRemoveDir=d:\bar 

REM If I use %exampleRemoveDir% it does not work at all. 
call :removeFromPath exampleRemoveDir & set result=%ERRORLEVEL% 

:removeFromPath 
set removeDir=%~1 

setlocal enableextensions enabledelayedexpansion 
set _=!PATH:%removeDir%;=! 
if "%_%" == "%PATH%" set _=!PATH:%removeDir%=! 
endlocal & set PATH=%_% 
echo %PATH% 
exit /b 0 

但是與解決途徑仍保持不變。代碼完美無缺地工作,如果我沒有將刪除步驟的範圍縮小,因爲我想爲多個目錄執行該操作,如果沒有這樣一個好幫手爲我完成這項工作真的很痛苦。

EDIT 2

因爲這似乎比我還以爲這裏是我的完整不變的腳本,使複雜得多。

@echo off 
:: Switching Perl version from ActivePerl to StrawberryPerl or the other way round depending on which paths are set in 
:: PATH. 

:: Directories for ActivePerl 
set activePerl_SiteBinPath=D:\ProgramFiles\ActivePerl\site\bin 
set activePerl_BinPath=D:\ProgramFiles\ActivePerl\bin 

:: Directories for StrawberryPerl 
set strawberryPerl_SiteBinPath=D:\ProgramFiles\StrawberryPerl\perl\site\bin 
set strawberryPerl_BinCPath=D:\ProgramFiles\StrawberryPerl\c\bin 
set strawberryPerl_BinPath=D:\ProgramFiles\StrawberryPerl\perl\bin 

:: Determine which of the directories are present in PATH and which are not. 
call :isInPath %activePerl_SiteBinPath% & set foundActivePerl_SiteBinPath=%ERRORLEVEL% 
call :isInPath %activePerl_BinPath% & set foundActivePerl_BinPath=%ERRORLEVEL% 
call :isInPath %strawberryPerl_SiteBinPath% & set foundStrawberryPerl_SiteBinPath=%ERRORLEVEL% 
call :isInPath %strawberryPerl_BinCPath% & set foundStrawberryPerl_BinCPath=%ERRORLEVEL% 
call :isInPath %strawberryPerl_BinPath% & set foundStrawberryPerl_BinPath=%ERRORLEVEL% 

:: Test 
call :removeFromPath %strawberryPerl_SiteBinPath% & set removedStrawberryPerl_SiteBinPath=%ERRORLEVEL% 

rem if /i %foundActivePerl_SiteBinPath% equ 0 if /i %foundActivePerl_BinPath% equ 0 (
rem  if /i %foundStrawberryPerl_SiteBinPath% neq 0 if /i %foundStrawberryPerl_BinPath% neq 0 if /i %foundStrawberryPerl_BinCPath% neq 0 (
rem   echo Switching from ActivePerl to StrawberryPerl. 
rem   TODO 
rem   exit /b 0 
rem ) 
rem) 
rem 
rem if /i %foundStrawberryPerl_SiteBinPath% equ 0 if /i %foundStrawberryPerl_BinPath% equ 0 if /i %foundStrawberryPerl_BinCPath% equ 0 (
rem  if /i %foundActivePerl_SiteBinPath% neq 0 if /i %foundActivePerl_BinPath% neq 0 (
rem   echo Switching from StrawberryPerl to ActivePerl. 
rem   TODO 
rem   exit /b 0 
rem ) 
rem) 

:: Error 
:: TODO 
exit /b 

:isInPath 
:: Tests if the path stored within variable pathVar exists within %PATH%. 
:: 
:: The result is returned as the ERRORLEVEL: 
::  0 if the pathVar path is found in %PATH%. 
::  1 if pathVar path is not found in %PATH%. 
::  2 if parhVar path is missing or undefined. 

:: Error checking 
if "%~1"=="" exit /b 2 

set pathVar=%~1 

for /f %%i in ('echo ";%%PATH%%;" ^| find /c /i ";%pathVar%;"') do set /a foundPathVar=%%i 

if /i %foundPathVar% equ 0 (
    exit /b 1 
) 
exit b/ 0 

:removeFromPath 
:: Removes a given directory from environment variable PATH if the directory exists within PATH. 
:: 
:: The result is returned as the ERRORLEVEL: 
::  0 if the given directory was removed from PATH or if it didn't exist in PATH. 
::  1 if no directory was given or the directory is undefined. 

:: Error checking 
if "%~1"=="" exit /b 2 

set removeDir=%~1 

setlocal enableextensions enabledelayedexpansion 
set _=!PATH:%removeDir%;=! 
if "%_%" == "%PATH%" set _=!PATH:;%removeDir%=! 
endlocal & set PATH=%_% 
echo %PATH% 

exit /b 0 

編輯3

由於@Anders從路徑現在刪除目錄工作正常。我刪除了上面未定義參數的錯誤檢查,並在函數調用的參數周圍添加了%。 但不知何故:isInPath現在總是返回零。就我而言,這已經奏效了......:/此外,使用當前代碼(在所有函數參數中添加了%),在調用:removeFromPath後,cmd總是直接關閉,而不管pause。真是令人生氣!

+0

爲什麼你想從'%PATH%'變量刪除位置?您是否知道,您在批處理/ cmd.exe會話中使用'SET'PATH =%PATH:match = replace%「進行的任何更改都不是先決條件,它只會持續與cmd實例一樣長。你能否提供更多的批處理文件,以便我們更好地處理你希望達到的目標。 – Compo

+0

@Lilo,腳本中是否有其他功能可能導致問題?我測試了安德斯的腳本,確實確實刪除了路徑中的目錄。 –

+0

從長遠來看,我想使用setx,但只要它不能與set一起工作,爲什麼我會使用setx? 我已經安裝了ActivePerl以及es StrawberryPerl,我希望能夠通過簡單地雙擊批處理腳本來切換當前使用的Perl變體。爲了實現這一點,我必須檢查哪些目錄當前在PATH中,因此必須刪除或添加以從當前使用的變體切換到另一個。 – Lilo

回答

2

如果您想使用另一個變量作爲變量替換的一部分,則需要使用延遲擴展。您還需要處理您要移除的路徑在%path%末尾的可能性,因此不會由;終止。

@echo off 

set removedir=d:\bar 
set PATH=c:\foo;%removedir%;y:\baz&REM Set example %path% 

echo Starting with %%PATH%% set to %PATH% 

setlocal enableextensions enabledelayedexpansion 
set _=!PATH:%removedir%;=! 
if "%_%" == "%PATH%" set _=!PATH:;%removedir%=! 
endlocal & set PATH=%_% 

echo %%PATH%% is now %PATH% 

,並在這裏作爲一個輔助功能:

@echo off 
goto start 

:removeFromPath 
echo.Debug: Starting function with remove=%~1 and %%PATH%%=%PATH% 
setlocal enableextensions enabledelayedexpansion 
set removedir=%~1 
set _=!PATH:%removedir%;=! 
if "%_%" == "%PATH%" set _=!PATH:;%removedir%=! 
endlocal & set PATH=%_% 
echo.Debug: Ending function with %%PATH%%=%PATH% 
goto :EOF 


:start 
set exampleremovedir=d:\bar 
set PATH=c:\foo;%exampleremovedir%;y:\baz&REM Set example %path% 

echo Starting with %%PATH%% set to %PATH% 

call :removeFromPath %exampleremovedir% 

echo %%PATH%% is now %PATH% 
+0

只要我不把它放到一個函數中, ':removeFromPath'我在那裏設置removedir =%〜1',然後使用你的代碼,即使在那個函數裏面的回顯顯示了一個不變的路徑,我在這裏丟失了什麼? – Lilo

+0

對我來說它工作得很好。 – Anders

+0

@Lilo有你試圖在函數內部設置'setlocal enabledelayedexpansion'? –

相關問題