迭代十六進制來創建jpeg文件

Question

我有一個帶有十六進制行的文本文件。我希望每行都轉換成jpeg.file，因爲它們是照片。我能做到這一點單獨使用binascii.a2b_hex像這樣（我已經縮短了十六進制）：

data = binascii.a2b_hex("FFD8FFE") 
with open('image.jpg', 'wb') as image_file: 
    #image_file.write(data) 

現在，我想這是散裝的。所以我有一個帶有十六進制行的文本文件，我希望每個十六進制都寫入他自己的jpeg文件。我想，我幾乎沒有，但我的代碼給了我這個錯誤：

ValueError: too many values to unpack 

下面是代碼：

import binascii 
text_file = open("photos-clean.txt", "w") 

#for each hexadecimal, put it in between single quotes so it becomes a string. Also remove the first two chars from a line. 
with open('photos.txt', 'r') as f: 
    for i in f: 
     photo = i[2:] 
     quotes = "'" + photo.rstrip() + "'" 
     print quotes 
     text_file.write(quotes) 
     text_file.write("\n") 

text_file.close() 

#for each hexadecimal, transform it to a jpeg with binascii and write it to his own jpeg.file 
with open("photos-clean.txt", "r") as f2: 
    for i, data in (f2): 
     transform = binascii.a2b_hex(i) 
     with open('photo{}.jpg'.format(transform), 'wb') as output: 
      output.write(data) 

編輯：我找到了答案，這是我應該做了：

import binascii 
text_file = open("photos-clean.txt", "w") 


with open('photos.txt', 'r') as f: 
    for i in f: 
     photo = i[2:] 
     text_file.write(photo) 
     text_file.write("\n") 

text_file.close() 


with open("photos-clean.txt", "r") as f2: 
    count=0 
    for i in f2: 
     count = count + 1 
     cleaned = i.strip("\r\n") 
     transform = binascii.a2b_hex(cleaned) 
     with open("{}.jpg".format(count), 'wb') as output: 
      output.write(transform) 

Answer 1

我想你有錯誤在線for i, data in (f2):。 你試圖從f2中解壓2個值和數據，我想你需要枚舉如下。 此外，我想你想使用我的索引文件名和寫，而不是數據變換成輸出

with open("photos-clean.txt", "r") as f2: 
    for i, data in enumerate(f2): 
     transform = binascii.a2b_hex(data) 
     with open('photo{}.jpg'.format(i), 'wb') as output: 
      output.write(transfrom)