sql - 添加時間間隔跳過一定的時間段

Question

我有一個mySql查詢，它爲datetime字段添加了一定的時間間隔。

UPDATE table T 
    SET T.ending = DATE_ADD(T.ending, INTERVAL T.hours * 3600 * some_other_variable_factors SECONDS)) 

現在，我需要檢測是否有新的結束時間在幾個小時之間（假設20:00至06:00），這應該從計算中排除。

即，如果以前的結局是今天19:58我們加了4分鐘，新的結局應該是明天06:02

另外的困難是添加的時間量可能大於24小時。 所以，如果舊的結局是今天，19.00，我們將24小時，新的結局應該後天是天，15.00（這聽起來是一個非常糟糕的電影的標題;）

有沒有辦法在實現這一目標MySQL的？在一個查詢中？我也在考慮存儲過程，但我沒有任何經驗。

一些測試數據：

CREATE TABLE IF NOT EXISTS `tt` (
     `source` datetime NOT NULL, 
     `hours` int(11) NOT NULL, 
     `off_start` int(11) NOT NULL, 
     `off_long` int(11) NOT NULL, 
     `correct` datetime NOT NULL  
    ) ENGINE=InnoDb; 


    INSERT INTO `tt` (`source`, `hours`, `off_start`, `off_long`, `correct`) VALUES 
    ('2010-11-11 12:00:00', 1, 20, 10, '2010-11-11 13:00:00'), 
    ('2010-11-11 19:00:00', 1, 20, 10, '2010-11-12 06:00:00'), 
    ('2010-11-11 19:00:00', 2, 20, 10, '2010-11-12 07:00:00'), 
    ('2010-11-11 19:00:00', 3, 20, 10, '2010-11-12 08:00:00'), 
    ('2010-11-11 19:00:00', 24, 20, 10, '2010-11-13 15:00:00'), 
    ('2010-11-11 19:00:00', 48, 20, 10, '2010-11-15 11:00:00'), 
    ('2010-11-11 19:00:00', 72, 20, 10, '2010-11-17 07:00:00'); 

Answer 1

SELECT CASE 
     WHEN HOUR((t_ending + INTERVAL some_other_variable_factors HOUR) - INTERVAL 20 HOUR) < 10 THEN 
       t_ending + INTERVAL some_other_variable_factors HOUR + INTERVAL 10 HOUR 
     ELSE 
       t_ending + INTERVAL some_other_variable_factors HOUR 
     END 
FROM mytable 

INTERVAL 20 HOUR意味着你的截止時間開始於20:00，INTERVAL 10 HOUR意味着持續10小時（20:00直到06:00）。相應地調整。

更新：

SET @hours = 54; 

SELECT CAST('2010-01-01 15:00:00' + INTERVAL @hours HOUR AS DATETIME); 

-- 
2010-01-03 21:00:00 


SELECT CASE 
     WHEN HOUR(CAST('2010-01-01 15:00:00' + INTERVAL @hours HOUR AS DATETIME) - INTERVAL 20 HOUR) < 10 THEN 
       CAST('2010-01-01 15:00:00' + INTERVAL @hours HOUR + INTERVAL 10 HOUR AS DATETIME) 
     ELSE 
       CAST('2010-01-01 15:00:00' + INTERVAL @hours HOUR AS DATETIME) 
     END; 

-- 
2010-01-04 07:00:00 

Answer 2

在單個查詢有點棘手，但此查詢應該工作：

 
-------------- 
SELECT source, correct, hours_to_end, (source + INTERVAL hours_to_end HOUR) ending 
FROM (
    SELECT source, correct 
     , LEAST(hours, hours_to_off) 
      + (((hours_left - MOD(hours_left, on_long))/on_long) * 24 
      + off_long 
      + MOD(hours_left, on_long)) * overlap hours_to_end 
    FROM (
     SELECT source, correct, hours, on_long, off_long, hours_to_off 
      , GREATEST(0, hours - hours_to_off) hours_left 
      , IF(hours - hours_to_off >= 0, 1, 0) overlap 
     FROM (
      SELECT source, correct, hours, off_long 
       , (24 - off_long) on_long 
       , HOUR(TIMEDIFF(DATE(source) + INTERVAL off_start HOUR, source)) hours_to_off 
      FROM tt 
     ) t 
    ) t 
) t 
-------------- 

+---------------------+---------------------+--------------+---------------------+ 
| source    | correct    | hours_to_end | ending    | 
+---------------------+---------------------+--------------+---------------------+ 
| 2010-11-11 12:00:00 | 2010-11-11 13:00:00 |  1.0000 | 2010-11-11 13:00:00 | 
| 2010-11-11 19:00:00 | 2010-11-12 06:00:00 |  11.0000 | 2010-11-12 06:00:00 | 
| 2010-11-11 19:00:00 | 2010-11-12 07:00:00 |  12.0000 | 2010-11-12 07:00:00 | 
| 2010-11-11 19:00:00 | 2010-11-12 08:00:00 |  13.0000 | 2010-11-12 08:00:00 | 
| 2010-11-11 19:00:00 | 2010-11-13 15:00:00 |  44.0000 | 2010-11-13 15:00:00 | 
| 2010-11-11 19:00:00 | 2010-11-15 11:00:00 |  88.0000 | 2010-11-15 11:00:00 | 
| 2010-11-11 19:00:00 | 2010-11-17 07:00:00 |  132.0000 | 2010-11-17 07:00:00 | 
+---------------------+---------------------+--------------+---------------------+ 

編輯：這裏是一個較短的版本：

 
SELECT source, correct 
    , source 
    + INTERVAL LEAST(hours, hours_to_off) 
     + IF(hours-hours_to_off >= 0 
     ,(hours-hours_to_off-MOD(hours-hours_to_off, on_long))/on_long*24 
      + off_long + MOD(hours-hours_to_off, on_long) 
     ,0) HOUR ending 
FROM (
    SELECT source, correct, hours, off_long, (24-off_long) on_long 
     , HOUR(TIMEDIFF(DATE(source)+INTERVAL off_start HOUR, source)) hours_to_off 
    FROM tt 
) t 
; 

Answer 3

這是mine：

CREATE PROCEDURE do_update() 
BEGIN 

DECLARE @offhoursperday, @hours, @days, @remaininghours INT 
DECLARE @offhoursstart, @offhoursend TIME 

SET @offhoursstart = CAST('22:00' AS TIME) 
SET @offhoursend = CAST('06:00' AS TIME) 
SET @hours = 54 
SET @days = @hours/(24 - @offhoursperday) 
SET @remaininghours = @hours % (24 - @offhoursperday) 

UPDATE table T 
    SET T.ending = 
    CASE 
     WHEN ((HOUR(TIMEDIFF(@offhoursstart, TIME(T.ending))) + 24) % 24) < @remaininghours 
     THEN DATE_ADD(DATE_ADD(T.ending, INTERVAL @days DAY), INTERVAL @remaininghours HOUR) 
     ELSE DATE_ADD(DATE_ADD(T.ending, INTERVAL @days DAY), INTERVAL (@remaininghours + @offhoursperday) HOUR) 
    END 

END