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不知道如何解決這個錯誤,我評論了代碼中的錯誤,對於Java來說很新穎。我正嘗試將我的卡片發送到我的構造函數中,並創建一個卡組數組。不兼容型卡無法轉換爲字符串
public abstract class CardGame {
protected String[] deck = new String[52];
private String[] Suit = {"Spade","Dimond","Heart","Club"};
private String[] Card = {"2","3","4","5","6","7","8","9","10","jack","queen","king","ace"};
public CardGame(){
int c = 0;
for (int x=0; x < Suit.length; ++x){
for (int i = 0; i < Card.length; ++i){
deck[c] = new Card(Suit[x], Card[i]); // heres the error
c++;
}
}
}
}
public class Card {
String suit;
String name;
public Card(String s,String n){
suit = s;
name = n;
}
public String getsuit(){
return suit;
}
public String getname(){
return name;
}
}
TYVM奏效,所以即時通訊與保護卡[] =甲板新卡猜測[52];我創建了一個卡數據類型數組? oop很混亂。 – user3538292 2014-10-07 02:40:07
@ user3538292將您的數據結構(您的數組)看作只適合特定類型對象的容器,就像一個蛋盒只能包含雞蛋一樣,或者一個保齡球包只能包含保齡球。保齡球不屬於蛋殼,也不屬於蛋殼。當你聲明一個數據結構時,你也告訴Java編譯器它內部屬於什麼類型的東西(特定類的典型對象或從該類繼承的對象)。你編寫得越多,你越習慣這個想法。請記住:每件事都有特定的地方。 – MarsAtomic 2014-10-07 18:54:11