我如何接受這個計劃的多個客戶？

Question

通過大量的學習和研究，我編寫了一個服務器端程序。但是這個程序的問題在於它不接受多個客戶端，我也想知道如何將輸出發送回客戶端，而不是在服務器端顯示。有人可以幫我拿出代碼嗎？這是我試過至今 -

類節目 {

private static Regex _regex = new Regex("not|http|console|application", RegexOptions.Compiled | RegexOptions.IgnoreCase | RegexOptions.CultureInvariant); 


    static void Main(string[] args) 
    { 
     { 

      TcpListener serversocket = new TcpListener(8888); 
      TcpClient clientsocket = default(TcpClient); 
      serversocket.Start(); 

      Console.WriteLine(">> Server Started"); 
      clientsocket = serversocket.AcceptTcpClient(); 
      Console.WriteLine("Accept Connection From Client"); 

      try 
      { 
       using (var reader = new StreamReader(clientsocket.GetStream())) 
       { 
        string line; 
        int lineNumber = 0; 
        while (null != (line = reader.ReadLine())) 
        { 
         lineNumber += 1; 
         foreach (Match match in _regex.Matches(line)) 
         { 

          Console.WriteLine("Line {0} matches {1}", lineNumber, match.Value); 
         } 
        } 
       } 
      } 
      catch (Exception ex) 
      { 
       Console.Error.WriteLine(ex.ToString()); 
      } 
      clientsocket.Close(); 
      serversocket.Stop(); 
      Console.WriteLine(" >> exit"); 
      Console.ReadLine(); 
     } 
    } 
    } 

Answer 1

你可以將其更改爲這樣的事情。

static void Main(string[] args) 
{ 
    TcpListener serversocket = new TcpListener(8888); 
    TcpClient clientsocket = default(TcpClient); 
    serversocket.Start(); 

    Console.WriteLine(">> Server Started"); 
    while(true) 
    { 
     clientsocket = serversocket.AcceptTcpClient(); 
     Console.WriteLine("Accept Connection From Client"); 
     LineMatcher lm = new LineMatcher(clientsocket); 
     Thread thread = new Thread(new ThreadStart(lm.Run)); 
     thread.Start(); 
     Console.WriteLine("Client connected"); 
    } 

    serversocket.Stop(); 
    Console.WriteLine(" >> exit"); 
    Console.ReadLine(); 
} 

再有這種獨立的類處理linematching

public class LineMatcher{ 
    private static Regex _regex = new Regex("not|http|console|application", RegexOptions.Compiled | RegexOptions.IgnoreCase | RegexOptions.CultureInvariant); 

    private TcpClient _client; 

    public LineMatcher(TcpClient client) 
    { 
     _client = client; 
    } 

    public void Run() 
    { 
     try 
     { 
      using (var reader = new StreamReader(_client.GetStream())) 
      { 
       string line; 
       int lineNumber = 0; 
       while (null != (line = reader.ReadLine())) 
       { 
        lineNumber += 1; 
        foreach (Match match in _regex.Matches(line)) 
        { 

         Console.WriteLine("Line {0} matches {1}", lineNumber, match.Value); 
        } 
       } 
      } 
     } 
     catch (Exception ex) 
     { 
      Console.Error.WriteLine(ex.ToString()); 
     } 
     Console.WriteLine("Closing client"); 
     _client.Close(); 
    } 
} 

這純粹是一個概念證明，是沒有辦法穩定的代碼;）
請注意，這不管理子任何方式的線程。
還有沒有正確的方式關閉聆聽者，因爲（true）