語法錯誤：未結束的字符串與JSON陣列

所以我有...語法錯誤：未結束的字符串與JSON陣列

var newfavz = 'Array (


[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "] 
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "] 
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "] 

) 
';

我的console.log，但不知何故，有一個語法錯誤：未結束的字符串。我環顧四周，嘗試使用諸如str_replace「/」和「//」之類的方法，或者像.replace（/ ^/+/g，''）這樣的正則表達式。因爲它看起來像JavaScript不允許將字符串分成多行或類似的東西。

這一切都始於一個SQL查詢，像這樣......

$favurl = []; 
$favquery = "SELECT * FROM userfavs WHERE users = '$username'"; 
$favresult = mysqli_query($conn, $favquery); 

while($row = mysqli_fetch_assoc($favresult)) { 

array_push($favurl, $row['fav_id']);

之後，我做了

var newfavz = <?php print_r ($favurl); ?>

導致以上。

有沒有什麼辦法可以用來解決語法錯誤？謝謝！

來源

2017-08-05 HotPotatos

'echo'結果。打印的字符串在JavaScript環境中是無用的，檢查https://stackoverflow.com/questions/4885737/pass-a-php-array-to-a-javascript-function – undefined

啊對不起，我在使用print_r進行調試時:) – HotPotatos

原因多行字符串不允許在JS：

"A 
B"

是一個語法錯誤。你可能會刪除所有換行符，並與\ n替換它們，或者你使用模板文字：

`A 
B`

在您的代碼：

var newfavz =` <?php print_r ($favurl); ?>`;

這麼多有關錯誤。但字符串仍然不可用，需要解析。看看JSON或編寫自己的小解析器。

來源

2017-08-05 20:55:55

要添加到此，在服務器上，您應該傳遞給JS之前使用json_encode（）方法將數組編碼爲json對象。 – Adriani6

嘿，我忘了添加這個問題，但是我在將數據插入SQL數據庫之前使用了JSON_encode方法。到目前爲止，我發現刪除這個未終止的字符串文字錯誤的唯一方法是做另一個JSON_encode，這非常愚蠢的IMO。 – HotPotatos

嘿男人''事情工作完美，非常感謝！ – HotPotatos

要麼使用ES6 template literals：

var newfavz = `Array (


[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "] 
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "] 
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "] 

) 
`;

或者用反斜槓：

var newfavz = 'Array (\n\ 
\n\ 
\n\ 
[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n\ 
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n\ 
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n\ 
\n\ 
)\ 
';

或連接：

var newfavz = 'Array (\n' + 
    '\n' + 
    '\n' + 
    '[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n' + 
    '[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n' + 
    '[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n' + 
    '\n' + 
    ')\n';

\n用於表示一個newline。

來源

2017-08-05 20:56:48 Svenskunganka

謝謝你！我用了''字符，它完美的工作！ – HotPotatos

你必須放一個反斜槓在每行的末尾有一個多行字符串：json_encode`而不是使用`print_r`的`

var newfavz = 'Array (\ 
[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\ 
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\ 
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\ 
)\ 
';

來源

2017-08-05 20:57:08 DyZ

語法錯誤：未結束的字符串與JSON陣列

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