Mysql添加簡單排名表

嗨我想簡單地添加1,2,3,4,5,6,7,8,9,10等級。Mysql添加簡單排名表

我的輸出現在給出如下：

USER ID | SCORE 
2  | 10242 
13231 | 3427 
23732 | 3378 
24638 | 2934 
23468 | 1898

我儘量做到的是：

RANK | USER ID | SCORE 
#1 | 2  | 10242 
#2 | 13231 | 3427 
#3 | 23732 | 3378 
#4 | 24638 | 2934 
#5 | 23468 | 1898

這是我的PHP：

<?php $result = mysql_query("SELECT * FROM `users_score` ORDER BY `users_score`.`score` DESC LIMIT 0 , 10") or die(mysql_error()); 
if(mysql_num_rows($result) > 0): ?> 
<table> 
    <tr> 
     <th style="text-align:left;">ID</th> 
     <th style="text-align:left;">SCORE</th> 
    <tr> 
    <?php while($row = mysql_fetch_assoc($result)): ?> 
    <tr> 
     <td><?php echo $row['user_id']; ?></td> 
     <td style="font-weight: bold; color: #008AFF;"><?php echo $row['score']; ?></td> 
    </tr> 
    <?php endwhile; ?> 
</table> 
<?php endif; ?>

有一個簡單的像數這個功能？

來源

2013-02-12 swordsecurity

If you just want changes in your php here is the code... 

<?php 
$result = mysql_query("SELECT * FROM `users_score` ORDER BY `users_score`.`score` DESC LIMIT 0 ,10") or die(mysql_error()); 

$rank=0; 
$temp_score=0; 

if(mysql_num_rows($result) > 0): ?> 
<table> 
    <tr> 
     <th style="text-align:left;">RANK</th> 
     <th style="text-align:left;">ID</th> 
     <th style="text-align:left;">SCORE</th> 
    <tr> 
    <?php while($row = mysql_fetch_assoc($result)): 
     if($temp_score!=$row['score']) 
      $rank++; 
    ?> 
    <tr> 
    <td><?php echo "#".$rank; ?></td> 
    <td><?php echo $row['user_id']; ?></td> 
    <td style="font-weight: bold; color: #008AFF;"><?php echo $row['score']; ?></td> 
    </tr> 
    <?php 
     $temp_score=$row['score]; 
     endwhile; ?> 
</table> 
<?php endif; ?>

來源

2013-02-12 12:25:45 jsherchan

非常感謝！ – swordsecurity 2013-02-12 23:43:17

你可以通過使用變量來查詢。

SELECT @row:[email protected]+1 as RankNo, 
     a.UserID, 
     a.Score 
FROM tableName a, (SELECT @row:=0) b 
ORDER BY a.Score DESC

SQLFiddle Demo

，但它有一個缺點，它不處理扳平比分

，如果你想在排名添加#，cancatenate的RankNo with＃`

UPDATE 1

SELECT CONCAT('#', @row:[email protected]+1) as RankNo, 
     a.UserID, 
     a.Score 
FROM tableName a, (SELECT @row:=0) b 
ORDER BY a.Score DESC

SQLFiddle Demo

來源

2013-02-12 12:04:01

SELECT (@rank := @rank + 1) AS rank, user_id, score 
FROM ( SELECT user_id, score 
     FROM scores, (SELECT @rank := 0) AS vars 
     ORDER BY score DESC) AS h

SQLFiddle

來源

2013-02-12 12:04:37

我不認爲嵌套查詢會獲得任何結果。我錯過了什麼嗎？ – StarNamer 2013-02-12 12:23:53

可能不是在這種情況下，但有一些例如「GROUP BY」，它需要排序和嵌套1st，然後SELECT。只是玩它安全，但這樣做:) – 2013-02-12 12:25:49

你所尋找的是一個相當於MS SQL的ROW_NUMBER（）函數。這在之前已被回答，例如here或here

答案就是使用類似：

SELECT @rn:[email protected]+1 as RANK, ID, SCORE 
     FROM `users_score`, (SELECT @rn:=0) as rn 
     ORDER BY `users_score`.`score` DESC LIMIT 0

更新

只是爲了興趣，搬運匹配得分可以在SQL中完成：

SELECT @rn := @rn + case (@ls-SCORE) when 0 then 0 else @s end as RANK, 
     ID, 
     SCORE, 
     @s := case (@ls-SCORE) when 0 then @s+1 else 1 end as STEPSIZE, 
     @ls := SCORE as LASTSCORE 
FROM `users_score`.`score` a, 
     (SELECT @rn := 0) b, 
     (SELECT @ls := max(SCORE)+1 FROM `users_score`.`score`) c, 
     (SELECT @s := 1) d 
ORDER BY a.Score DESC LIMIT 0

然而，如果你想這樣做，那麼在PHP代碼中更容易。

來源

2013-02-12 12:17:39 StarNamer

Mysql添加簡單排名表

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