我有以下條件代碼,如果具有相應用戶名的記錄不存在,它將插入新記錄,並在記錄存在時更新記錄。這工作正常。sql更新時不會覆蓋現有信息
但是,目前,如果我插入一條新記錄,並且只插入名字和姓氏,並且可能地址詳細信息中的電話信息被留爲空白,這很好。如果我希望只用電話記錄更新記錄,則名稱和地址信息將被替換爲無。
我想知道的是,如果它可能有一個簡單的方法來填充我的PHP的HTML形式更新信息,與我將更新字段的內容?我使用
<input type="text" name="uniquename" />
爲了得到用戶輸入,然後將其傳遞給javascript函數,然後將其傳遞迴下面PHP代碼。如果這是不可能的,有沒有一種簡單的方法來工作一些SQL/PHP的魔術,只更新一個字段相應的userinput不是空的?
$usernameQuery = "select username from USERS where username = '" . $con->escape_string($username) . "'";
$xblah = $con->query($usernameQuery);
while ($row = mysqli_fetch_assoc($xblah))
{
$checkUsername = $row['username'];
}
if ($checkUsername == null) {
$userQuery = "INSERT INTO USERS VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
if ($userInfo = $con->prepare($userQuery)) {
$userInfo->bind_param("ssssssssssssssssssss", $username, $firstname, $lastname, $flaggedauctions, $lastauction, $street1, $city1, $postcode1, $street2, $city2, $postcode2, $phone, $mobilephone, $fax, $email, $website, $bank, $banknumber, $accountnumber, $comments);
$userInfo->execute();
$userInfo->close();
echo "true";
} else {
echo "false";
}
print_r($con->error);
}
else if ($checkUsername == $username) {
$userQuery = "UPDATE USERS SET firstname = ?, lastname = ?, flaggedauctions = ?, lastauction = ?, street1 = ?, city1 = ?, postcode1 = ?, street2 = ?, city2 = ?, postcode2 = ?, phone = ?, mobilephone = ?, fax = ?, email = ?, website = ?, bank = ?, banknumber = ?, accoutnumber = ? WHERE username = ?";
if ($userInfo = $con->prepare($userQuery)) {
$userInfo->bind_param("sssssssssssssssssss", $firstname, $lastname, $flaggedauctions, $lastauction, $street1, $city1, $postcode1, $street2, $city2, $postcode2, $phone, $mobilephone, $fax, $email, $website, $bank, $banknumber, $accountnumber, $username);
$userInfo->execute();
$userInfo->close();
echo "true";
} else {
echo "false";
}
print_r($con->error);
}
嗯,謝謝。 bindArgs發生了什麼? – 2009-04-16 04:05:10
我的PHP技巧有點生疏,但我認爲你可以將$ bindArgs傳遞給bind_param函數。 我相信你可以將數組傳遞給PHP中的可變數字參數函數。 – oscarkuo 2009-04-16 04:17:43