如何獲取NSString的NSArray鍵值？

-1

我有很多NSArray的，像這樣但林不知道如何讓每個數組的鍵值像Boots或Dress Shoes如何獲取NSString的NSArray鍵值？

編輯：我不是試圖讓Boots IM的值試圖拿到鑰匙Boots，Dress Shoes等等。

test { 
    Boots =  (
     Brogue, 
     Chelsea, 
     Chukka, 
     Dress, 
     "Rain/Snow", 
     Rugged 
    ); 
    "Dress Shoes" =  (
     Oxfords, 
     "Formal Shoes" 
    ); 
    "Loafers/Slip-ons" =  (
     "Slip-ons", 
     Loafers 
    ); 
    Sandals =  (
     "Flip Flops", 
     Slides 
    ); 
    Sneakers =  (
     "Low Top", 
     "High Tops", 
     "Running Shoes", 
     "Slip-ons" 
    ); 
}

我如何獲得價值的Boots，Dress Shoes等？

來源

2016-11-04 Farhan Syed

如果你希望能夠通過名稱來訪問他們，你最好能夠將其存儲在一個NSDictionary。如果沒有，那麼你會想要使用'NSArray.objectAtIndex' – brandonscript

我試過'objectAtIndex：indexPath.row'爲一個UITableView，它已經崩潰 –

@brandonscript你可能會誤解，我不想獲得什麼裏面「啓動「試圖獲得密鑰」啓動「它的自我 –

由於您沒有提供正確的JSON響應。我用了你上面的JSON建立在我的項目在本地一個，並用它解析

請找我在我的項目

使用Sample.json

{ 
    "test": { 
     "Boots": [ 
        "Brogue", 
        "Chelsea", 
        "Chukka", 
        "Dress", 
        "Rain/Snow", 
        "Rugged" 
        ], 
     "Dress Shoes": [ 
         "Oxfords", 
         "Formal Shoes" 
         ], 
     "Loafers/Slip-ons": [ 
          "Slip-ons", 
          "Loafers" 
          ], 
     "Sandals": [ 
        "Flip Flops", 
        "Slides" 
        ], 
     "Sneakers": [ 
        "Low Top", 
        "High Tops", 
        "Running Shoes", 
        "Slip-ons" 
        ] 
    } 
}

樣品JSON文件

我用下面的代碼來獲取數組值。有兩種方法來解析和獲取數組值。

方法1

NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Sample" ofType:@"json"]; 

    NSError * error; 
    NSString *fileContents = [[NSString alloc] initWithContentsOfFile:filePath encoding:NSUTF8StringEncoding error:&error]; 

    if(error) 
    { 
     NSLog(@"Error reading file: %@",error.localizedDescription); 
    } 

    NSDictionary *dataList = [NSJSONSerialization JSONObjectWithData:[fileContents dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableContainers error:NULL]; 

    NSLog(@"%@",dataList); 
    NSDictionary *sourceData = [dataList objectForKey:@"test"]; 
    NSArray * boots = [sourceData objectForKey:@"Boots"]; 
    NSArray * shoes = [sourceData objectForKey:@"Dress Shoes"]; 
    NSArray * loafers = [sourceData objectForKey:@"Loafers/Slip-ons"]; 
    NSArray * sandals = [sourceData objectForKey:@"Sandals"]; 
    NSArray * sneakers = [sourceData objectForKey:@"Sneakers"]; 

    NSLog(@"\n %@ \n %@ \n %@ \n %@ \n %@",boots,shoes,loafers,sandals,sneakers);

方法2

NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Sample" ofType:@"json"]; 

     NSError * error; 
     NSString *fileContents = [[NSString alloc] initWithContentsOfFile:filePath encoding:NSUTF8StringEncoding error:&error]; 

     if(error) 
     { 
      NSLog(@"Error reading file: %@",error.localizedDescription); 
     } 

     NSDictionary *dataList = [NSJSONSerialization JSONObjectWithData:[fileContents dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableContainers error:NULL]; 

     NSLog(@"%@",dataList); 
     NSDictionary *sourceData = [dataList objectForKey:@"test"]; 

NSArray *keyValues = [sourceData allKeys]; 

    for (int i =0 ; i < keyValues.count; i++) { 
     NSArray *innerContents = [sourceData objectForKey:[keyValues objectAtIndex:i]]; 
     NSLog(@"%@ \n", innerContents); 
    }

來源

2016-11-04 04:01:45 Vinodh

如何獲取NSString的NSArray鍵值？

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