我有一個登錄div /頁面。此時,登錄表單有一個外部文件config.php的動作。每當用戶點擊提交,當然它會去config.php文件,如果用戶登錄失敗,在config.php文件中,用戶將重定向到login.html頁面。如果登錄失敗,則在配置文件中顯示回顯
我現在的問題是如果用戶無法登錄,如何在窗體底部/底部回顯它?
這是我的代碼:
<?php
session_start();
// include connection file
include("configPDO.php");
$member_email=$_POST['member_email'];
$member_password=$_POST['member_password'];
$return = mysql_real_escape_string($_POST['return']);
$STM = $dbh->prepare("SELECT * FROM customer WHERE member_email = :member_email AND member_password = :member_password");
$STM->bindParam(':member_email', $member_email);
$STM->bindParam(':member_password', $member_password);
$STM->execute();
$count = $STM->rowCount();
$row = $STM -> fetch(PDO::FETCH_ASSOC);
if ($count == 1) {
session_start();
$_SESSION['login_id'] = $row['member_id'];
$_SESSION['member_name'] = $row['member_name']; // added
$_SESSION['member_email'] = $row['member_email']; // added
//echo 'SESSION =' .$_SESSION['myusername'];
//echo 'ROW =' .$row['myusername'];
//var_dump($row);
if ($_SESSION['login_id'] != '' || $_SESSION['login_id'] > 0) { // edited
header("Location: http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']);
} else {
header("location: .$return");
}
}
else
{
header("location:.$return");
}
$dbh = null;
?>
這是我的形式:
<form method="post" enctype="multipart/form-data" action="config-login.php">
<table width="345" align="center" style="background:honeydew; vertical-align:top; margin:0px auto; border:solid medium yellowgreen;">
<td class="myimage">Email :</td>
<td width="196" style="padding-right:2px;"><input type="text" name="member_email" style="width:100%"/></td>
</tr>
<tr>
<td class="myimage">Password : </td>
<td style="padding-right:2px;"><input type="password" name="member_password" style="width:100%"/></td>
</tr>
<tr>
</table>
<p style="background:greenyellow; display:block; width:100%; overflow:hidden; padding:10px 0;">
<input class="myimage" style="margin-right:10px; padding:0 10px; float:right;" type="submit" value="Register"/></p>
</form>
而且我想顯示登錄在表格的底部失敗。有人可以幫忙嗎?非常感謝你。
[UPDATE]
我已經使用由@Mour解釋代碼和代碼工作等魅力。 Hoewever,我忘了一件事,如果這個登錄表單是通過點擊功能與JavaScript顯示的,這意味着如果點擊login
的文本,則會顯示此登錄表單。所以我現在想要的是,如果登錄失敗,我想保持這個登錄表單不斷點擊登錄文本不斷顯示。
<li>
<a href = "javascript:void(0)"
onclick ="document.getElementById('light').style.display='block';
document.getElementById('fade').style.display='block'">Login</a></li>
</ul>
<!--Black Overlay-->
<div id="fade" class="black_overlay" onLoad="initDynamicOptionLists()"></div>
<!--Pop Up Div-->
<div id="light" class="white_content">
<div id="loginbox">
<span id="login-form">Login</span>
<form method="post" action="config-login.php">
<table width="345" align="center" style="background:honeydew; vertical-align:top; margin:0px auto; border:solid medium yellowgreen;">
<tr>
<td class="myimage">Email :</td>
<td width="196" style="padding-right:2px;"><input type="text" name="member_email" style="width:100%"/></td></tr>
<tr>
<td class="myimage">Password : </td>
<td style="padding-right:2px;"><input type="password" name="member_password" style="width:100%"/></td></tr>
</table>
<div style="background:greenyellow; display:block; width:100%; overflow:hidden; margin:10px 0; padding:10px 0;">
<input type="hidden" name="return" value="<?php echo $_SERVER['REQUEST_URI']; ?>" />
<p><?php
if($_GET['result']=='failed'){
echo 'invalid login';
}?>
</p>
<input class="myimage" style="margin-right:10px; padding:0 10px; float:right;" type="submit" value="Login"/>
<span style="position: absolute; top: 11px; right:1px; color:white;" id="closeBlocked">
<a style="color:green; text-decoration:none; background:white; padding:10px;"
href = "javascript:void(0)"
onclick ="document.getElementById('light').style.display='none';
document.getElementById('fade').style.display='none'"><b>X</b></a></span>
</div>
</form>
</div>
</div>
<!-- End of Pop Up Div-->
您可以使用Ajax來實現這一點。 – 2014-11-06 05:22:45
在'session'中設置錯誤消息並將其打印在查看頁面中。 – 2014-11-06 05:27:38
............怎麼樣? – klaudia 2014-11-06 05:29:37