如果/ else語句在循環內部被忽略

-1

當我運行這個，並且我遇到了情況1中表示「輸入颶風＃1的最大速度：」的行時，我將輸入「34」並且它將返回「風速在結：25.6789」「輸入颶風＃2的最大風速：」但我試圖讓它返回「無效Windspeed爲Hurrican，再試一次。」如果/ else語句在循環內部被忽略

#include <stdio.h> 
#include <stdlib.h> 

int main(int argc, char *argv[]) 
{ 
int x; 
int year; 
int tropical_storms; 
int hurricanes; 
int a=1; 
int windspeed; 
float knots; 
float conversion=0.868976; 
    printf("     HEg v1.0 \n"); 
    printf("0. Exit\n"); 
    printf("1. Submit Hurricane Season Storm Information\n"); 
    printf("2. Submit Storm Data\n"); 
    printf("3. Print Hurricane Season Analysis\n"); 
    printf("4. Print Storm Analysis\n"); 
    printf("\n"); 
    printf("Please Enter Selection: "); 
    scanf("%d", &x); 
    switch(x) { 
    case 0: 
      printf("Thank you for using HEg v1.0"); 
      break; 
    case 1: 
      printf("Enter the year: "); 
      scanf("%d", &year); 
      printf("Enter the number of tropical storms in 2009: "); 
      scanf("%d", &tropical_storms); 
      printf("Enter the number of Hurricanes in 2009: "); 
      scanf("%d", &hurricanes); 
      while(a<=hurricanes){ 
       printf("Enter the max windspeed of hurricane #%d: ", a); 
       scanf("%d", &windspeed); 
       a++; 
       if(windspeed>74){ 
       knots=windspeed*conversion; 
       printf("Wind speed in knots: %.4f \n", knots); 
       } 
       else{ 
       printf("Invalid Windspeed for Hurricane. Try again"); 
       } 
      } 

      break; 
    case 2: 
      printf("Menu option not available in HEg v1.0"); 
      break; 
    case 3: 
      printf("Menu option not available in HEg v1.0"); 
      break; 
    case 4: 
      printf("Menu option not available in HEg v1.0"); 
      break; 
    default: 
      printf("no");  
      break; 
    } 
    system("PAUSE>nul"); 
    return 0; 
}

來源

2014-09-26 CCorey

你爲什麼認爲'if' /'else'語句被忽略？ – 2014-09-26 01:54:12

作爲一名經驗豐富的程序員，我可以向您保證，if語句不會被忽略:)請更新您的文章，說出*您預期會發生什麼*以及*實際發生了什麼*。還要描述你給了哪些輸入來引起這種行爲。 – 2014-09-26 02:06:06

目前尚不清楚「聲明中的內容」的含義。 – 2014-09-26 02:06:31