在postgres中聚合多個列

我在聚合時遇到值問題。我的表是這樣的：在postgres中聚合多個列

CREATE TABLE test2 (a_date date, a_actif integer[], a_registred integer[], a_filter integer, sum_actions integer); 
INSERT INTO test2 VALUES 
('2016-12-15', array[1,2,3], array[1,4], 5, 2), 
('2016-12-15', array[5], array[1,4], 2, 20), 
('2016-12-15', array[6,2,3], array[2,3], 3, 10), 
('2016-12-15', array[8,2,3], array[4,1], 1, 4);

目標是算上不同a_actif和a_registred，並獲得總和，每日期，動作的數量。這應該是這樣的：

----------------------------------------------------------- 
| Date | Active_count | Register_count | sum_actions | 
----------------------------------------------------------- 
|2016-12-15| 6   |  4   | 36   | 
-----------------------------------------------------------

Active_count：a_actif

Register_count的DISTINCT ID：的a_registred

所以我做了這樣的事情DISTINCT ID，但行動的總和是錯誤的

SELECT f.date, COUNT(DISTINCT f.actifs), COUNT(DISTINCT f.registers), SUM(sum_actions) 
FROM 
( 
SELECT unnest(a_actif) as actifs, a_date as date, unnest(a_registred) as registers, sum_actions 
FROM test2 
WHERE a_filter IN ('1','2','3','5') 
) f 
--WHERE date BETWEEN XX and YY 
GROUP BY f.date;

任何想法？

http://rextester.com/CXWG2246

來源

2016-12-15 TLR

檢查你的''unnest'without組by' http://rextester.com/OTMU9161是顯然你爲什麼得到錯誤的總和。只需在分開的子查詢中計算總和即可。讓我知道是否需要更多的指導方針 –

SQL DEMO

WITH t_count as (
    SELECT f.date, COUNT(DISTINCT f.actifs), COUNT(DISTINCT f.registers) 
    FROM 
    ( 
     SELECT unnest(a_actif) as actifs, 
       a_date as date, 
       unnest(a_registred) as registers 
     FROM test2 
     WHERE a_filter IN ('1','2','3','5') 
    ) f 
    --WHERE date BETWEEN '2016-09-01' AND '2016-09-01' 
    GROUP BY f.date 
), t_sum as (
    SELECT a_date as date, SUM(sum_actions) total 
    FROM test2 
    WHERE a_filter IN ('1','2','3','5')  
    --WHERE date BETWEEN '2016-09-01' AND '2016-09-01' 
    GROUP BY date 
)   
SELECT t1.*, t2.total 
FROM t_count t1 
JOIN t_sum t2 
    ON t1.date = t2.date

輸出

來源

2016-12-15 17:31:14

在postgres中聚合多個列

回答

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