2016-08-15 45 views
0

我有一個很大的問題... 只需運行該程序,然後轉到「New Gun」,然後選擇「Handgun」。 當您必須輸入模型時,就會出現問題。 例如,如果我輸入「沙漠之鷹」,在文本文件中它只輸出「鷹」。它很奇怪,我無法解決它。從字符串中讀取整行的C++

代碼:

#include <fstream> 
#include <iostream> 
#include <windows.h> 
#include <string> 
#include <algorithm> 
#include <sstream> 
using namespace std; 

void setcolor(unsigned short color) 
{ 
HANDLE hcon = GetStdHandle(STD_OUTPUT_HANDLE); 
SetConsoleTextAttribute(hcon,color); 
} 

int main(){ 

system("chcp 1251 > nul"); 
system("title GunnZone"); 


string gunModel; 
int gunManufactureYear; 
int itemNumber; 
double gunWeight; 
double price; 

ofstream myfileHandguns("Handguns.txt", ios::app); 
ofstream myfileRifles("Rifles.txt", ios::app); 
ofstream myfileShotguns("Shotguns.txt", ios::app); 
ofstream myfileSnipers("Snipers.txt", ios::app); 
ofstream myfileGranades("Granades.txt", ios::app); 
ofstream myfileExplosives("Explosives.txt", ios::app); 


int choice; 
cout << "1.New Gun" << endl; 
cout << "2.List Guns" << endl; 
cout << "3.Exit" << endl << endl; 
cout << "Enter your choice: "; 
cin >> choice; 

if(choice == 1){ 

    system("cls"); 

    int gunTypeChoice; 
    cout << "1.Handgun" << endl; 
    cout << "2.Rifle" << endl; 
    cout << "3.Shotgun" << endl; 
    cout << "4.Sniper" << endl; 
    cout << "5.Granade" << endl; 
    cout << "6.Explosives" << endl << endl; 
    cout << "Enter your choice: "; 
    cin >> gunTypeChoice; 

    if(gunTypeChoice == 1){ 

     system("cls"); 

     cout << "Model: "; 
     cin >> gunModel; 
     getline(cin, gunModel); 
     cout << endl << endl; 

     cout << "Year of Manufacture: "; 
     cin >> gunManufactureYear; 
     cout << endl << endl; 

     cout << "Weight: "; 
     cin >> gunWeight; 
     cout << endl << endl; 

     cout << "Item Number: "; 
     cin >> itemNumber; 
     cout << endl << endl; 

     cout << "Price: "; 
     cin >> price; 


     myfileHandguns << "Model: " << gunModel << "\n\n"; 
     myfileHandguns << "Year of Manufacture: " << gunManufactureYear << "\n\n"; 
     myfileHandguns << "Weight: " << gunWeight << " g" << "\n\n"; 
     myfileHandguns << "Item Number: " << itemNumber << "\n\n"; 
     myfileHandguns << "Price: " << price << "$" << "\n\n"; 
     myfileHandguns.close(); 
    } 

} 

system("pause > nul"); 
return 0; 

}

+3

因爲'CIN >> gunModel;'獲取 「沙漠」,然後'函數getline(CIN,gunModel);'獲取「鷹」。嘗試刪除'cin >> gunModel;'。 – DimChtz

+0

刪除cin,並添加getline? 是的,我試過但看看會發生什麼... 當我去添加一把槍它錯過了「型號:」,並剛剛開始在製造年...... –

+0

編輯您的問題,並實施DimChtz的建議。你只需要刪除一行。 –

回答

2

刪除>>操作者的建議。使用clearignore來清除錯誤跳過換行符\n

cout << "Model: "; 
//cin >> gunModel; 
std::cin.clear(); 
std::cin.ignore(0xffff, '\n'); 
std::getline(cin, gunModel); 
cout << "Testing... you entered " << gunModel << endl; 
cout << endl << endl; 

參見Why would we call cin.clear() and cin.ignore() after reading input?

+0

非常感謝你! 現在我明白了。 –

+0

您可以單擊複選標記接受答案 –