curl命令6

Question

我目前打的API，在終端中輸入以下命令：

curl -u me@website.com:ACCESS_TOKEN https://api.website.com/api/v1/ -D -

我怎樣才能用在Xcode用斯威夫特和AFNetworking相同的結果的響應6？

如何更改以下代碼以實現我的需求？

func searchInstagramByHashtag(searchString: String) { 
    for subview in self.scrollView.subviews { 
     subview.removeFromSuperview() 
    } 

    let instagramURLString = "https://api.instagram.com/v1/tags/" + searchString + "/media/recent?client_id=" + instagramClientID 

    let manager = AFHTTPRequestOperationManager() 

    manager.GET(instagramURLString, 
     parameters: nil, 
     success: { (operation: AFHTTPRequestOperation!,responseObject: AnyObject!) in 
      println("JSON: " + responseObject.description) 

      if let dataArray = responseObject.valueForKey("data") as? [AnyObject] { 
       self.scrollView.contentSize = CGSizeMake(320, CGFloat(320*dataArray.count)) 
       for var i = 0; i < dataArray.count; i++ { 
        let dataObject: AnyObject = dataArray[i] 
        if let imageURLString = dataObject.valueForKeyPath("images.standard_resolution.url") as? String { 
         println("image " + String(i) + " URL is " + imageURLString) 

         let imageView = UIImageView(frame: CGRectMake(0, CGFloat(320*i), 320, 320)) 
         self.scrollView.addSubview(imageView) 
          imageView.setImageWithURL(NSURL(string: imageURLString)) 
        } 
       } 
      } 
     }, 
     failure: { (operation: AFHTTPRequestOperation!,error: NSError!) in 
      println("Error: " + error.localizedDescription) 
    }) 
} 

如果我無法使用Swift和AFNetworking，我應該採取什麼其他方法？

Answer 1

更改URL的第一部分應該工作：

http://USER_NAME:ACCESS_TOKEN@api.instagram.com/...