入門JSON數據

Question

我JSON數據，如本內嵌套的地圖：

var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}' 

它實際上是被退回來的JSON。例如，我只是在這裏顯示它。我可以用data["credit"]獲得所謂credit的元素，但只得到我：

{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]} 

我怎麼能深入到一個鏡頭？ data["credit"]["credit"]是不正確的語法。它導致未定義。我知道我很接近但不記得其他人。我們的目標是從JSON數據中獲取149.96。

Answer 1

使用.操作來獲取對象的對象

alert(data.credit.credit) //gives 149.96 
alert(data.credit.amount) //gives 149.96 
alert(data.credit.card) //gives NT2C8FFC 

Answer 2

您正在data字符串不是一個對象。變化

var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}' 

到

var data = {"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}} 

如果你不能改變原有的數據，你需要做

data = JSON.parse(data); 

（這將在大多數瀏覽器工作）或使用解析它來自庫的方法，如JQuery's：

data = jQuery.parseJSON(data); 

Answer 3

現在您可以使用alert(data.credit.credit)。

 var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}'; 
     eval("data=" + data); 
     alert(data.credit.credit); 

您還可以使用data = JSON.parse(data);字符串爲JSON轉換但這瀏覽器兼容性問題。

這些是支持

• 火狐（Mozilla的）瀏覽器3.5
• 的Internet Explorer 8
• 鉻
• 歌劇10
• 列表項
• 的Safari 4

舊版本不支持。