2010-07-23 44 views

回答

2

該類已經存在於Java SE API中:java.net.URL

InputStream input = new URL("http://localhost/context/page.jsf").openStream(); 
+0

嗨,有沒有辦法做到這一點,但用Beans內容處理xhtml? – dcalap 2014-03-04 17:23:41