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select first_name, last_name, uid from user where uid in (select uid2 from friend where uid1=me() and uid2 **not** in(SELECT user_id FROM like WHERE object_id={0}))
但是,這並不是不被Facebook所認可。你如何解決這個問題? 如果沒有,你會得到喜歡的東西的所有朋友的列表fql選擇不喜歡特定Facebook項目的朋友