Question

我有一個網站，我有一個數據庫的所有帳戶和whatnot，另一個用於存儲用戶在網站上完成的操作。

每個用戶都有自己的表格，但是我想合併每個用戶組（所有「被鏈接在一起」的用戶）的數據，並在操作發生時對數據進行排序。

這是我的;

<?php 
$query = "SELECT `TALKING_TO` FROM `nnn_instant_messaging` WHERE `AUTHOR` = '" . DISPLAY_NAME . "' AND `TALKING_TO` != ''"; 
$query = mysql_query($query, $CON) or die("_error_ " . mysql_error()); 
if(mysql_num_rows($query) != 0) { 
    $table_str = ""; 
    $select_ref_clause = "("; 
    $select_time_stamp_clause = "("; 
    while($row = mysql_fetch_array($query)) { 
     $table_str .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . "`, "; 
     $select_ref_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".REF`, "; 
     $select_time_stamp_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".TIME_STAMP`, "; 
    } 
    $table_str = $table_str . "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; 
    $select_ref_clause = substr($select_ref_clause, 0, -2) . ") AS `REF`, "; 
    $select_time_stamp_clause = substr($select_time_stamp_clause, 0, -2) . ") AS `TIME_STAMP`";  
}else{ 
    $table_str = "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; 
    $select_ref_clause = "`REF`, "; 
    $select_time_stamp_clause = "`TIME_STAMP`"; 
} 
$where_clause = $select_ref_clause . $select_time_stamp_clause; 

$query = "SELECT " . $where_clause . " FROM " . $table_str . " ORDER BY TIME_STAMP"; 
die($query); 
$query = mysql_query($query, $CON) or die("_error_ " . mysql_error()); 
if(mysql_num_rows($query) != 0) { 

}else{ 
?> 
<p>Currently no actions have taken place in your network.</p> 
<?php 
} 
?> 

上面的代碼返回的SQL語句：

SELECT (`actvbiz_networks`.`john_doe.REF`, `actvbiz_networks`.`Emmalene_Jackson.REF`) AS `REF`, (`actvbiz_networks`.`john_doe.TIME_STAMP`, `actvbiz_networks`.`Emmalene_Jackson.TIME_STAMP`) AS `TIME_STAMP` FROM `actvbiz_networks`.`john_doe`, `actvbiz_networks`.`Emmalene_Jackson`, `actvbiz_networks`.`act_web_designs` ORDER BY TIME_STAMP 

我真的對我的腳學習與SQL。

它不是PHP我有一個問題（我可以非常高興地用PHP代碼）;這只是對SQL語句的幫助。

任何幫助非常感謝。

Answer 1

沒有花時間通過你的代碼，但從聽起來像你想要聯合的問題。

SELECT 
3 AS a 
UNION SELECT 
2 AS a 
UNION SELECT 
1 AS a 
ORDER BY a 

給人

 
a 
= 
1 
2 
3 

編輯：所以，或許這樣的事情？

DROP TEMPORARY TABLE IF EXISTS t1; 
DROP TEMPORARY TABLE IF EXISTS t2; 
DROP TEMPORARY TABLE IF EXISTS tmp; 

CREATE TEMPORARY TABLE t1 (
a INT(11) 
); 

CREATE TEMPORARY TABLE t2 (
b INT(11) 
); 

INSERT INTO t1 VALUES (1), (2), (3); 
INSERT INTO t2 VALUES (4), (5), (6); 

CREATE TEMPORARY TABLE tmp 
SELECT 
b AS f 
FROM t2 
UNION SELECT 
a AS f 
FROM t1 
ORDER BY f; 

SELECT * FROM tmp; 

回報

 
f 
= 
1 
2 
3 
4 
5 
6 

Answer 2

你試過用view？這樣，您可以使用UNION作爲simendsjo建議，並且所有內容都放在一個表中。這不是一個臨時的解決方案，而是一個非常好的，乾淨而有效的方法。

Answer 3

我endeed了使用simendsjo的提示問題和使用UNION ALL

<?php 
$query = "SELECT `TALKING_TO` FROM `nnn_instant_messaging` WHERE `AUTHOR` = '" . DISPLAY_NAME . "' AND `TALKING_TO` != ''"; 
$query = mysql_query($query, $CON) or die("_error_ " . mysql_error()); 
if(mysql_num_rows($query) != 0) { 
    while($row = mysql_fetch_array($query)) { 
     $table_str = 'SELECT REF, ACTION, TIME_STAMP, DATA, IMAGE, DISPLAY_NAME FROM actvbiz_networks.' . $row['TALKING_TO'] . ' UNION ALL '; 
    } 
}else{ 
    $table_str = ""; 
} 
$table_str = $table_str . 'SELECT REF, ACTION, TIME_STAMP, DATA, IMAGE, DISPLAY_NAME FROM actvbiz_networks.' . DISPLAY_NAME . ' ORDER BY TIME_STAMP DESC'; 

$query = mysql_query($table_str, $CON) or die("_error_ " . mysql_error()); 
if(mysql_num_rows($query) != 0) { 
    while($rows = mysql_fetch_array($query)) {