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嗨我使用此代碼發送任何號碼的短信,但它是第一次工作,並沒有下一次。任何修復? MY_PERMISSION_REQUEST_SEND_SMS中有問題嗎?有沒有其他簡短的方法發送短信?不發送消息
public class MainActivity extends AppCompatActivity {
private static final int MY_PERMISSIONS_REQUEST_SEND_SMS =0 ;
String phonenumber;
EditText number;
String message;
Button btn;
EditText txt;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btn = (Button) findViewById(R.id.send);
txt = (EditText) findViewById(R.id.message);
number = (EditText) findViewById(R.id.Number);
btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
SendSms();
}
});
}
protected void SendSms() {
phonenumber=number.getText().toString();
message= txt.getText().toString();
if (ContextCompat.checkSelfPermission(this,
Manifest.permission.SEND_SMS)
!= PackageManager.PERMISSION_GRANTED) {
if (ActivityCompat.shouldShowRequestPermissionRationale(this,
Manifest.permission.SEND_SMS)) {
} else {
ActivityCompat.requestPermissions(this,
new String[]{Manifest.permission.SEND_SMS},
MY_PERMISSIONS_REQUEST_SEND_SMS);
}
}
}
@Override
public void onRequestPermissionsResult(int requestCode,String permissions[],
int[] grantResults) {
switch (requestCode) {
case MY_PERMISSIONS_REQUEST_SEND_SMS: {
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED)
{
SmsManager smsManager = SmsManager.getDefault();
smsManager.sendTextMessage(phonenumber, null, message, null,
null);
Toast.makeText(getApplicationContext(), "SMS sent.",
Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(),
"SMS faild, please try again.",
Toast.LENGTH_LONG).show();
return;
}
}
}
}
}
它真的幫助。謝謝 –