導航xml節點;

-5

嗨我有一個xml數據從另一個服務返回。它看起來像這樣導航xml節點;

<?xml version="1.0" encoding="UTF-8"?> 
<response xmlns="http://test.com/group/application" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
<Response> 
<Response> 
<ReturnCode>0</ReturnCode> 
<Message>Sucess</Message> 
<Data>PRINT 'This is a test #2'</Data> 
</Response> 
</Response> 
</response>

我需要Data，Message和ReturnCode的值。數據（PRINT「這是一個試驗＃2」）節點內的值可以是單線或上千行..

我使用此C＃代碼以獲得值

XmlDocument的XM =新的XmlDocument （）;

 string Response = obj.getContent(str, 1, 73810, SHA); 



     //Console.WriteLine("Response" + Response); 
     xm.LoadXml(Response); 



     Console.WriteLine(xm.InnerXml); 

     XmlNode oldCd; 
     XmlElement root = xm.DocumentElement; 
     Console.WriteLine(root.InnerText); 
     oldCd = root.SelectSingleNode("/response/Response/Response/ReturnCode/Message/Data/");

static void Main() 
    { 
     try 
     { 

      svc obj = new svc(); 
      .. 
      //XmlDocument xm = new XmlDocument(); 

      string rsp = obj.getContent(..; 


      String myEncodedString; 
      myEncodedString = obj.XmlDecode(rsp); 

      XNamespace xmlns = XNamespace.Get("http://xxxx.com/xxx/xx"); 

      XDocument doc = XDocument.Parse(myEncodedString); 

      Console.WriteLine(obj.Return_Message_Data("ReturnCode", myEncodedString)); 

      Console.WriteLine(obj.Return_Message_Data("Message", myEncodedString)); 

      Console.WriteLine(obj.Return_Message_Data("Data", myEncodedString));    

      Console.ReadLine(); 
     } 

     catch (Exception e) 
     { 
      Console.WriteLine(e); 
      Console.ReadLine(); 
     } 

    }

來源

2015-10-20 jramacha

你最好開始再編碼！ –

是的，我從c＃應用程序訪問這個。我是 XmlDocument xm = new XmlDocument（）; 串RSP = obj.getContent（STR，1，73810，SHA）; xm.LoadXml（Rsp）; Console.WriteLine（xm.InnerXml）; XmlNode oldCd; XmlElement root = xm.DocumentElement; Console.WriteLine（root.InnerText）; oldCd = root.SelectSingleNode（「/ response/Response/Response/ReturnCode/Message/Data /」）; 但我在Data列中沒有看到任何值。謝謝 – jramacha

您需要提出具體問題。這聽起來更像是你想要一個完整的解決方案。 – leigero

試試這個

XmlDocument xml = new XmlDocument(); 
xml.LoadXml(myXmlString); //myXmlString is the xml file in string //copying xml to string: string myXmlString = xmldoc.OuterXml.ToString(); 
XmlNodeList xnList = xml.SelectNodes("/responset[@*]/Response"); 
foreach (XmlNode xn in xnList) 
{ 
XmlNode response = xn.SelectSingleNode("Response"); 
if (response != null) 
{ 
string rc = response["ReturnCode"].InnerText; 
string msg = example["Message"].InnerText; 
string data = example["Data"].InnerText; 
} 
}

來源

2015-10-20 14:36:18

這沒有奏效 – jramacha

導航xml節點;

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