也許問題與掃描號碼 - ç

Question

可能重複：
Program not doing what it should - C

你好，

下面的程序只能讀取輸入的數字，當魯爾房屋被侵犯別停下來，但1大問題是，它不會停止閱讀數字，更糟的是，不要在屏幕上打印它應該如何。

代碼：

#include <stdio.h> 
#include <string.h> 

void SIFT(int x_arr[ ], int y_arr[]); 

int main() 
{ 
    int x[20] = {0} , y[20] = {0}; 
    int m=0,temp=0,curr=0,i=0,j=0; 

    printf("Please enter your numbers now:\n\n"); 

    /*enter numbers one by one. if x[i+1] value < x[i] value, err msg. 
     when user want to end the series he must enter '0' which means end of string (it wont  included in x[]) */ 
    while ((scanf("%d",&temp)) != '0') 
    { 
     if (temp >= curr) 
     { 
      x[i] = temp; 
      curr = temp; 
      i++; 
     } 
     else 
     { 
      printf("The numbers are not at the right order !\n\nProgram will now terminate...\n\n"); 
     } 
    } 

    SIFT(x,y); 

    for (i=0 ; y[i]=='0' ; i++) /*strlen(y) without ('0')'s includes*/ 
     m++; 

    /*Prints m , y's organs*/ 
    printf("\n\nm = %d",m); 
    printf("Y = "); 
    while (y[j]!='0') 
    { 
     printf ("%d ,",y[j]); 
     j++; 
    } 

return 0; 
} 

void SIFT(int x_arr[ ], int y_arr[]) 
{ 
    int i=0,j=0; 

    while (x_arr[i] != '0') 
    { 
     if (x_arr[i] == x_arr[i+1]) /*if current val. equals next val. -> jump dbl at x_arr*/ 
     { 
      y_arr[j] = x_arr[i]; 
      i+=2; 
      j++; 
     } 
     else 
     { 
      y_arr[j]=x_arr[i]; 
      i++; 
      j++; 
     } 
    }  

} 

請幫我解決這個問題... 日Thnx。

Answer 1

作爲第一個提示，scanf返回讀取的項目數，因此只有在讀取48個項目（ASCII值爲0）時纔會觸發條件(scanf("%d",&temp)) != '0'。這不會發生與格式說明符，所以這就是爲什麼你有循環。