有什麼方法可以查找查詢的值嗎？

Question

我最近做了一個系統，根據他們的積分對每個玩家進行排名。那麼系統獲得積分的方式相當混亂。在使用這個系統超過24小時後，我發現它沒有按照要點進行組織。但是後來突然想到，我可能會用一種不代表SQL查詢的方式來計算錯誤點。下面是我的排名使用我的SQL查詢：

SELECT * , playeruid AS player_id, (
(
    SELECT COALESCE(sum(player1points),0) 
    FROM `mybb_matches` 
    WHERE player1uid = player_id AND gid = $id AND timestamp < $time AND winneruid is NOT NULL AND dispute != 3) 
+ 
(
    SELECT COALESCE(sum(player2points),0) 
    FROM `mybb_matches` 
    WHERE player2uid = player_id AND gid = $id AND timestamp < $time AND winneruid is NOT NULL AND dispute != 3) 
+ 
(
    SELECT SUM(rank) 
    FROM `mybb_matchesgame` 
    WHERE playeruid = player_id AND gid = $id) 
) 

AS points 
FROM mybb_matchesgame WHERE gid = $id 
ORDER BY points DESC 

現在，這顯示，我在想，如果有任何的方式來攫取的「點」的值，並以某種方式顯示出來，所以我可以確認的數​​量。這可能嗎？

Answer 1

查詢中沒有按語句分組，因此SUM很可能不會超過預期集合。此外，COALESCE可以替換爲IFNULL，這可能會更有效一些。

SELECT q.* , playeruid AS player_id, a.points+b.points+c.points AS points 
FROM mybb_matchesgame q 
LEFT JOIN (
    SELECT IFNULL(SUM(player1points),0) as points,player_id 
    FROM `mybb_matches` 
    WHERE timestamp < $time AND winneruid is NOT NULL AND dispute != 3 
GROUP BY player_id) a ON player1uid = a.player_id 
LEFT JOIN (
    SELECT IFNULL(sum(player2points),0) as points,player_id 
    FROM `mybb_matches` 
    WHERE timestamp < $time AND winneruid is NOT NULL AND dispute != 3 
GROUP BY player_id) b ON player2uid = b.player_id 
LEFT JOIN (
    SELECT IFNULL(SUM(rank),0) as points,player_id 
    FROM `mybb_matchesgame` 
GROUP BY player_id) c ON playeruid = c.player_id 
    WHERE gid = $id 
ORDER BY a.points+b.points+c.points DESC;