將新行寫入輸出

Question

我一直在嘗試創建一個輸出文件，該文件寫入多個執行腳本，並從數組列表中獲取某個參數。到目前爲止，我得到混亂的重複輸出。我怎樣才能在每一行上獲得一個執行命令？這是我的。

$myArray = @(1,2,3) 

foreach ($element in $myArray) { 

$myobj = "EXECUTE [masterdb].[dbo].[update_rows] @row_num=" +"'"+$element+"'"+","+ "@status = 'Fail'" 
$myprocedure += $myobj 
$myobj = $null 
} 
Out-file -filepath $path -inputobject $myprocedure -width 50 -force 

Answer 1

$myprocedure永遠不會初始化爲數組，所以它成爲一個字符串，只需添加更多的文字。要麼你需要在執行線的末尾添加換行符：

$myobj = "EXECUTE [masterdb].[dbo].[update_rows] @row_num=" +"'"+$element+"'"+","+ "@status = 'Fail'" + [System.Environment]::NewLine 

或創建一個空數組稱爲$myprocedure第一：

$myArray = @(1,2,3) 

$myprocedure = @() 
$path = "test.txt" 

foreach ($element in $myArray) { 

    $myobj = "EXECUTE [masterdb].[dbo].[update_rows] @row_num=" +"'"+$element+"'"+","+ "@status = 'Fail'" 
    $myprocedure += $myobj 
    $myobj = $null 
} 
Out-file -filepath $path -inputobject $myprocedure -width 50 -force 

或追加3次到該文件：

$myArray = @(1,2,3) 

$path = "test.txt" 

#remove-item $path if necessary 

foreach ($element in $myArray) { 
    "EXECUTE [masterdb].[dbo].[update_rows] @row_num=" +"'"+$element+"'"+","+ "@status = 'Fail'" | Out-file -filepath $path -width 50 -force -Append 
}