填充列表的列表隨機物品

Question

我有一個列表的列表與一定範圍內：

l = [["this", "is", "a"], ["list", "of"], ["lists", "that", "i", "want"], ["to", "copy"]] 

而且單詞的列表：

words = ["lorem", "ipsum", "dolor", "sit", "amet", "id", "sint", "risus", "per", "ut", "enim", "velit", "nunc", "ultricies"] 

我需要創建的翻版列表的列表，但從另一個列表中挑選的隨機詞彙。

這是首先想到的，但沒有骰子。

for random.choice in words: 
    for x in list: 
    for y in x: 
     y = random.choice 

任何想法？先謝謝你！

Answer 1

您可以使用列表理解爲這樣的：

import random 
my_list = [[1, 2, 3], [5, 6]] 
words = ['hello', 'Python'] 

new_list = [[random.choice(words) for y in x] for x in my_list] 
print(new_list) 

輸出：

[['Python', 'Python', 'hello'], ['Python', 'hello']] 

這相當於：

new_list = [] 
for x in my_list: 
    subl = [] 
    for y in x: 
     subl.append(random.choice(words)) 
    new_list.append(subl) 

與您的數據。例如：

my_list = [['this', 'is', 'a'], ['list', 'of'], 
      ['lists', 'that', 'i', 'want'], ['to', 'copy']] 

words = ['lorem', 'ipsum', 'dolor', 'sit', 'amet', 'id', 'sint', 'risus', 
     'per', 'ut', 'enim', 'velit', 'nunc', 'ultricies'] 
new_list = [[random.choice(words) for y in x] for x in my_list] 
print(new_list) 

輸出：

[['enim', 'risus', 'sint'], ['dolor', 'lorem'], ['sint', 'nunc', 'ut', 'lorem'], ['ipsum', 'amet']] 

Answer 2

您不會將值存儲回您的列表中。嘗試：

for i in range(0, len(list)): 
    subl = list[i] 
    for n in range(0, len(subl)): 
     list[i][n] = random.choice(words) 

Answer 3

您應彙整清單列表，然後洗牌，然後重建。例如：

import random 

def super_shuffle(lol): 
    sublist_lengths = [len(sublist) for sublist in lol] 
    flat = [item for sublist in lol for item in sublist] 
    random.shuffle(flat) 
    pos = 0 
    shuffled_lol = [] 
    for length in sublist_lengths: 
    shuffled_lol.append(flat[pos:pos+length]) 
    pos += length 
    return shuffled_lol 

print super_shuffle([[1,2,3,4],[5,6,7],[8,9]]) 

打印：

[[7, 8, 5, 6], [9, 1, 3], [2, 4]] 

這會隨機在所有名單，不只是在一個單一的子表，並保證沒有的DUP。