在我的應用程序中,我將在第一次加載頁面時從服務器端獲取數據表格,並使用jqgrid進行渲染。將數據數據傳遞到jqgrid表中
當我請求下面的例子的DummyView
頁面時,Web瀏覽器彈出一條消息,要求我下載application/json
文件,表明有什麼是嚴重錯誤的,我似乎無法得到它的工作。這裏是我的jQuery代碼:
$(document).ready(function(){
$("#list4").jqGrid({
url:'../../ViewRecord/DummyView',
datatype:'JSON',
mtype: 'GET',
colNames:['Id','Name','Description'],
colModel:[
{name:'id',index:'id',width:55,resizable:true},
{name:'name',index:'name',width:90,resizable:true},
{name:'description',index:'description',width:120,resizable:true}],
pager: jQuery('#pager'),
rowNum:10,
rowList:[5,10,20,50],
sortname: 'Id',
sortorder: "desc",
viewrecords: true,
imgpath:'/images',
caption: 'My first grid'
});
});
這是我的ViewRecord/DummyView
控制器的方法:
public ActionResult DummyView()
{
var page = new { page = 1 };
var rows = new object[2];
rows[0] = new { id = 222, cell = new[] { "222", "Blue", "This is blue" } };
rows[1] = new { id = 2, cell = new[] { "2", "Red", "This is red" } };
//var endarray = new[] {page, rows};
var result = new JsonResult();
result.Data = new { page = 1, records = 2, rows, total = 1 };
return result;
}
任何想法如何得到的jqGrid與ASP.NET MVC的工作?
不知道你的答案如何解決我的問題;看到更新後的問題 – Graviton 2009-11-23 09:30:17